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| 13 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
The parabolas are shown in the graph below if there is a problem loading the applet.
When given a function, it is not always possible to use any value as an input. Sometimes the input will not make sense in the given context of the function. It could also be that the function is not defined for such value.
Function | Analysis | Domain |
---|---|---|
f(x)=3x | Multiplication by 3 is defined for all real numbers. | All real numbers |
g(x)=x | Square roots are not defined for negative numbers. | All non-negative numbers — that is, x≥0 |
h(x)=x1 | Division by zero is undefined. | All real numbers except 0 — that is, x=0 |
Given a function and its domain it is possible to study the set of all possible outputs.
The range of a function is the set of all y-values, or outputs, of the function. The range of a function depends on both the domain and the function itself. For example, consider the following functions and their defined domains.
Function | Domain |
---|---|
f(x)=2x | All integers |
g(x)=x2 | All real numbers |
h(x)=4 | All real numbers |
By analyzing the definition of each function along with the given domains, the ranges can be determined.
Function | Domain | Analysis | Range |
---|---|---|---|
f(x)=2x | All integers | The function takes any integer input and produces an output that is an even number, as each input is multiplied by 2. | All even numbers |
g(x)=x2 | All real numbers | The function takes any real number input and produces an output that is a non-negative number, as each input is squared. | All non-negative numbers — that is, y≥0 |
h(x)=4 | All real numbers | The function takes any real number input and sends it to 4. | Only the number 4 — that is, the range is {4} |
One of the characteristics of the graph of a quadratic function — a parabola — is the vertex.
a-value | Range |
---|---|
a>0 | [k,∞) |
a<0 | (-∞,k] |
P=60
LHS−2ℓ=RHS−2ℓ
LHS/2=RHS/2
Write as a difference of fractions
Calculate quotient
Rearrange equation
Commutative Property of Addition
Factor out -1
a=a+152−152
a2−2ab+b2=(a−b)2
Distribute -1
Calculate power
Since the vertex is at (15,225), the maximum area of the fence is 225, and this area is obtained by making a fence 15 feet long. It is not a coincidence that this is a square fence! Not every seedling can be protected from the deer, but Dominka and Emily did great.
It has been stated previously that the vertex of a parabola is either the absolute maximum or absolute minimum of the corresponding quadratic function. There is also an important characteristic of the quadratic function's graph that changes at this point.
A function is said to be increasing when, as the x-values increase, the values of f(x) also increase. On the other hand, the function is considered decreasing when, as x increases, f(x) decreases. An increasing interval is an interval of the independent variable where the function is increasing. A decreasing interval is an interval of the independent variable when the function is decreasing.
The two of them look around for the answer. They find a signboard that explains that the cart uses software that controls the lights. By knowing the function and stating the increasing and decreasing intervals, the lights can switch accordingly. The signboard shows the blueprints.
A quadratic function might cross the x- and y-axes. These points are known as intercepts.
The x-intercept of a line is the x-coordinate of the point where the line crosses the x-axis. The y-intercept of a line is the y-coordinate of the point where the line crosses the y-axis. The y-intercept of an equation is also known as its initial value.
Dominika and Emily, enjoying the theme park, want to try Shoot 'N' Hoop. If they make their one shot attempt, they will win a teddy bear. As the ball goes up, Dominika imagines her shot being modeled by a quadratic function.
The function representing Dominika's shot is graphed on the following coordinate plane. Take note that the drawn path of the ball in the air in the applet versus when mapped on the graph looks slightly different.
The height of the ball is represented by y, and time the ball is in the air after Dominika shoots the ball is x. The worker hosting the game tells Dominika and Emily that if they can answer the following math questions correctly, he will give them a second teddy bear.
Substitute values
Calculate power
-a(-b)=a⋅b
Multiply
Add terms
Put minus sign in numerator
Distribute -1
Calculate root
Parts of the graph of a quadratic function can be either above or below the x-axis. The intervals of x-values where this happens receive a special name.
A function is said to be positive where its graph is above the x-axis and is said to be negative where its graph is below the x-axis.
Emily and Dominika are relaxing on a bench at the theme park. Next to them, a bluebird appears in a bird bath! The bath seems to be a bit low on water, however. They look up the blueprints of similar birdbaths online and find a cross section of one that includes its quadratic function.
Positive Intervals: [0,0.5) and (5.5,6]
Negative Interval: (0.5,5.5)
The positive and negative intervals do not include the points where the function is equal to zero.
In general, the domain of quadratic functions consists of all real numbers. Investigating what happens to the function as the x-values increase or decrease infinitely is valuable in better understanding quadratic functions.
up.
down.
down and upor as
down-up.
Since quadratic functions are polynomial functions of degree 2 their end behavior is either up and up or down and down, all depending on the sign of the leading coefficient.
Rewrite 6x as 2⋅3x
a=a+32−32
a2−2ab+b2=(a−b)2
Calculate power
Subtract term
The given function models the rocket's height above the moon's surface t seconds after it begins its landing. This means that t=0 represents the initial time at which the rocket begins its landing. With this in mind, we will substitute t=0 into the given function rule and evaluate the result to find the height at which the rocket begins its landing. Let's do it!
Therefore, the rocket begins its landing when it is 1000 meters above the moon's surface. h(t)=t^2/90-20t/3+ 1000
Notice that the quadratic function is given in its standard form. f(x)=ax^2x+bx+ c In this form, c represents the constant term of the function. In other words, c is the value for f(0). f(0)= c Therefore, we can identify the value of h(0) by just looking the constant term of the given function which is 1000. l f(x)=ax^2x+bx+ c [0.5em] h(t)=t^2/90-20t/3+ 1000
We can find the height of the lowest point of this section of the roller coaster by finding the minimum of the function that describes it. To do so, we will rewrite the given function in vertex form. h(x)=a(x-h)^2+k Let's start by splitting the given function into factors and then factor out 0.5.
Now, we will rewrite the parenthesis by completing the square.
Great! With the quadratic function written in vertex form we can identify the coordinates of the vertex. Let's rearrange the signs of the terms as a final step! h(x)=0.5(x+5)^2+2 [0.5em] ⇓ [0.5em] h(x)=0.5(x-( -5))+ 2 The vertex of the function is at ( -5, 2). Since a>0 the parabola opens upwards, so 2 is the minimum of the function. Knowing this, we can conclude that the cart is 2 meters above the ground at its lowest point.
It is now Emily's turn at Shoot 'N' Hoop. She will shoot a basketball and try to win a teddy bear for this carnival game. Emily's shot is represented by the following equation and graph.
We are asked to find the x-intercepts of the quadratic equation, which is already written in standard form. We will begin by setting the given equation equal to 0 and identify the values of a, b, and c. ax^2+ bx+ c=0 ⇓ -16x^2+ 24x+ 8=0 In this case, a= -16, b= 24, and c= 8. We can now enter these values into the Quadratic Formula to solve this quadratic equation for x. x=- b±sqrt(b^2-4ac)/2a Let's substitute the values of a, b, and c into the formula!
Since negative values of time do not make sense in this scenario — the ball cannot be in the air for a negative amount of time — we will only consider the positive solution. The x-intercept represents the time the ball remains in the air, and we will round it down to two decimal places.
The ball is in the air for 1.78 seconds.