Substituting values from the domain will give the corresponding values from the range.
Practice makes perfect
The first thing to notice about this function is that there is a variable term missing. Let's try to rewrite it in standard form, Ax+ By= C, using 0 as the coefficient for our missing variable."
h(x)=-5 ⇔ 0x+ 1h(x)= -5We can graph the linear function using a table. First, let's select some arbitrary values from the domain, then substitute them for x in the given function. Solving for h(x) will give us the corresponding values from the range.
x
0x+h(x)=-5
Simplify
0
0( 0)+h( 0)=-5
h(0)= -5
2
0( 2)+h( 2)=-5
h(2)= -5
4
0( 4)+h( 4)=-5
h(4)= -5
Using these x and h(x) values as ( x, h(x)) coordinate pairs, we can plot the points. Connecting these points will give us the graph of the function.
