Big Ideas Math Integrated I, 2016
BI
Big Ideas Math Integrated I, 2016 View details
3. Function Notation
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Exercise 22 Page 125

Practice makes perfect
a The exercise gives us a function that describes the distance that light travels in t seconds.
d(t)=300 000t In the above formula, d(t) represents the distance, in kilometers, and t represents the time, in seconds. Calculating the distance that light travels in 15 seconds is the same as evaluating d(t) for t=15. We can do this by substituting 15 for every instance of t in the function.
d(t)=300 000 t
d( 15)=300 000( 15)
d(15)=4 500 000
In 15 seconds, light travels 4 500 000 kilometers.
b In this case, we are given the distance, and need to calculate the time.
d(t)=300 000 t Calculating the time it would take for light to travel 12 000 000 kilometers means that we will need to substitute this distance for d(t) in the function, and solve for t.
d(t)=300 000t
12 000 000=300 000t
12 000 000/300 000=300 000t/300 000
40=300 000t/300 000
40=300 000/300 000* t
40=1 * t
40=t
t=40
Light takes 40 seconds to travel 12 million kilometers.