We will start by the left-hand side, and then we will solve the .
Factoring
Consider the left-hand side of the equation.
x2+3x+2
Since the is
1, to factor this expression we will find two numbers whose sum is
3 and whose product is
2. 1+2=3and1⋅2=2
As we see above, the sum of
1 and
2 is
3, and their product is
2. Therefore, we will rewrite
3x as
x+2x.
x2+3x+2=0
x2+x+2x+2=0
x(x+1)+2(x+1)=0
(x+1)(x+2)=0
Solving
To solve this equation, we will apply the .
(x+1)(x+2)=0
x+1=0x+2=0(I)(II)
x=-1x+2=0
x=-1x=-2