Expand menu menu_open Minimize Start chapters Home History history History expand_more
{{ item.displayTitle }}
No history yet!
Progress & Statistics equalizer Progress expand_more
{{ filterOption.label }}
{{ item.displayTitle }}
{{ item.subject.displayTitle }}
No results
{{ searchError }}
{{ courseTrack.displayTitle }}
{{ statistics.percent }}% Sign in to view progress
{{ printedBook.courseTrack.name }} {{ printedBook.name }}
search Use offline Tools apps
Login account_circle menu_open

Factoring Quadratics

Factoring Quadratics 1.5 - Solution

arrow_back Return to Factoring Quadratics

We have a quadratic trinomial of the form Since there are no common factors, we will rewrite the linear term as the sum of two linear terms. The coefficients of these two terms will be factors of We have that and There are now three steps we need to follow in order to rewrite the above expression.

  1. Find Since we have that and the value of is
  2. Find factors of . Since which is negative, we need factors of to have opposite signs in order for the product to be negative. Since which is also negative, the absolute value of the negative factor will need to be greater than the absolute value of the positive factor, so that their sum is negative.

  1. Rewrite as two terms. Now that we know which factors are the ones to be used, we can rewrite as two terms.
Finally, we will factor the last expression obtained.