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Factoring Quadratics
Choose Course
Algebra 1
Quadratic Equations
Factoring Quadratics
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Factoring Quadratics 1.19 - Solution
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Return to Factoring Quadratics
Since the equation is already written in
factored form
, we will use the
Zero Product Property
to solve it.
(
4
x
+
3
)
(
x
+
2
)
=
0
ZeroProdProp
Use the Zero Product Property
4
x
+
3
=
0
x
+
2
=
0
(
I
)
(
II
)
SubEqn
(
I
):
LHS
−
3
=
RHS
−
3
4
x
=
-
3
x
+
2
=
0
DivEqn
(
I
):
LHS
/
4
=
RHS
/
4
x
=
4
-
3
x
+
2
=
0
MoveNegNumToFrac
(
I
):
Put minus sign in front of fraction
x
=
-
4
3
x
+
2
=
0
SubEqn
(
II
):
LHS
−
2
=
RHS
−
2
x
=
-
4
3
x
=
-
2
We found that the solutions to the equation are
x
=
-
4
3
and
x
=
-
2
.