Core Connections: Course 3
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2. Section 9.2
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Exercise 114 Page 433

Practice makes perfect
We want to simplify the following algebraic expression. 4x^3y* 3xy^2 To do so, we will use the Product of Powers Law. This law states that to multiply powers with the same base, we can add their exponents. In this case, we will also need to use the Commutative and Associative Properties of Multiplication. Let's do it!
4x^3y* 3xy^2
4* 3* x^3* x* y* y^2
(4* 3)* (x^3* x)* (y* y^2)
12* (x^3* x)* (y* y^2)

a=a^1

12* (x^3* x^1)* (y^1* y^2)
12* x^(3+1)* y^(1+2)
12 x^4 y^3
Let's consider the given expression. 6a^5b^2* 3ab^2 To simplify this expression, we can use the Product of Powers Law. Like in Part A, we will also need to use the Commutative and Associative Properties of Multiplication. Let's do it!
6a^5b^2* 3ab^2
6* 3* a^5* a* b^2* b^2
(6* 3)* (a^5* a)* (b^2* b^2)
18* (a^5* a)* (b^2* b^2)

a=a^1

18* (a^5* a^1)* (b^2* b^2)
18* a^(5+1)* b^(2+2)
18 a^6 b^4
We are asked to simplify the algebraic expression. m^2n* 9mn Again, we can do this using the Product of Powers Law and the Commutative and Associative Properties of Multiplication. Let's do it!
m^2n* 9mn
9* m^2* m* n* n
9* (m^2* m)* (n* n)

a=a^1

9* (m^2* m^1)* (n^1* n^1)
9* m^(2+1)* n^(1+1)
9 m^3 n^2
Let's consider the given expression. 3^5 * 8* 5^3/3^2* 2^3 * 5^3* 3^3 We want to simplify the expression. We can do this by using the Product of Powers Law and the Quotient of Powers Law. Recall that the Quotient of Powers Law states that to divide powers with the same base, we need to subtract their exponents. In this case, we will also use the Commutative and Associative Properties of Multiplication.
3^5 * 8* 5^3/3^2* 2^3 * 5^3* 3^3
3^5 * 8* 5^3/3^2* 3^3 * 2^3 * 5^3
3^5 * 8* 5^3/3^(2+3)* 2^3 * 5^3
3^5 * 8* 5^3/3^5* 2^3 * 5^3
3^5/3^5 * 8/2^3 * 5^3/5^3
3^5/3^5 * 8/8 * 5^3/5^3
3^5/3^5 * 1 * 5^3/5^3
3^(5-5)* 1 * 5^(3-3)
3^0 * 1 * 5^0
1* 1 * 1
1
We want to simplify the algebraic expression. m^4* n/n^3 We can start by factoring the expressions in both the numerator and denominator. Then we will cross out the common factors. Let's do it!
m^4* n/n^3
m * m * m * m * n/n* n* n
m * m * m * m * n/n* n* n
m * m * m * m/n* n
m^4/n^2
Let's analyze the given expression. 9a^4 b^2/15b To simplify the expression, we can start by factoring the expressions in both the numerator and denominator. Then we will cross out the common factors.
3* 3* a * a * a * a* b* b/3* 5 * b
3* 3* a * a * a * a* b* b/3 * 5 * b
3* a * a * a * a* b/5
3a^4b/5