Core Connections: Course 3
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2. Section 9.2
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Exercise 131 Page 437

Practice makes perfect

Remember that we can write any decimal number as a fraction where the denominator is some power of 10. With this in mind, let's write 0.7 as a fraction. 0.7=7/10

We want to write the given repeating decimal number as a fraction. 0.7 To do so, we will follow five steps.

  1. Assign a variable to represent the repeating decimal.
  2. Write an equation by setting the variable and the decimal equal to each other.
  3. Multiply both sides of the equation by 10 to some power, where the power is the number of repeating digits in the repeating decimal.
  4. Subtract the equivalent expressions from each side of the equation.
  5. Solve for the variable. Let's do it! First, we are going to use the variable N to represent the given repeating decimal number. This can be written as an equation. N=0.7 Since the given number has one repeating digit, we will multiply both sides of the equation by 10^1=10.
    N=0.7
    N* 10=0.7* 10
    10N=7.7
    We will now subtract N from both sides of the equation. Note that we will substitute 0.7 for N only on the right-hand side.
    10N=7.7
    10N-N=7.7-N
    10N-N=7.7- 0.7
    9N = 7
    Finally, we can solve the equation for N.
    9N=7
    9N/9=7/9
    N=7/9
    We found that 0.7 is equal to 79.
We want to write 0.15 as a fraction. Recall that we can write any decimal as a fraction where the denominator is some power of 10. 0.15=15/100 Notice that we can reduce the fraction we got. Let's do it!
15/100
15Ă· 5/100Ă· 5
3/20
We found that 0.15 is equivalent to 320.
Let's consider the given repeating decimal. 0.15 We can write this decimal as a fraction the same way we did in Part A. Again, we will use the variable N to represent the given decimal number. This can be written as an equation. N=0.15 Since the given number has two repeating digits, we will multiply both sides of the equation by 10^2=100.
N=0.15
N* 100=0.15* 100
100N=15.15
Let's now subtract N from both sides of the equation. Remember, we will substitute 0.15 for N only on the right-hand side.
100N=15.15
100N-N=15.15-N
100N-N=15.15- 0.15
99N = 15
Finally, let's solve the equation for N.
99N = 15
99N/99=15/99
N=15/99
N=15Ă· 3/99Ă· 3
N=5/33
We found that 0.15 is equal to 533.