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Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. $t+14≥15⇔t≥1$ This inequality tells us that all values greater than or equal to $1$ will satisfy the inequality. Thus, we can graph it on a number line with a closed circle at $1$ and the solution set represented to the right.

Note that the point on $-1$ is open because it's not included in the solution set.

The solution to the compound inequality is the combination of the solution sets. $t<-1ort≥1$ In the same way, the graph is a combination of the to separated graphs.

b

The compound inequality is now represented by the two solution sets. $z<-1orz>2$ The graph will be a combination of the two solution sets as well.