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We can solve the inequality by first subtracting $2$ from both sides and then dividing by $5.$

$12≤2+5x$

SubIneq$LHS−2≤RHS−2$

$10≤5x$

RearrangeIneqRearrange inequality

$5x≥10$

DivIneq$LHS/5≥RHS/5$

$x≥2$

The solution set of the inequality is $x≥2,$ that is, all $x$-values greater than or equal to $2.$

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