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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

7. Equations of Lines in the Coordinate Plane

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Exercise 62 Page 196

If an equation is in slope-intercept form, the slope of the line is given by the coefficient of x.

-1/6

Practice makes perfect

The given equation is already in written slope-intercept form. Let's start by identifying the slope. Slope-Intercept Form:& y= mx+b Given Equation:& y= -3ax-4In an equation written in slope-intercept form, m represents the slope. Therefore, we can say that -3a is the slope of the given equation. -3a=m To find the value of a such that the graph of the equation has slope 12, we should substitute this value for m and solve the above equation for a.

-3a=m

m= 1/2

-3a= 1/2

LHS * (-1/3)=RHS* (-1/3)

a=1/2(1/-3)

Multiply fractions

a=1/-6

MoveNegDenomToFrac

Put minus sign in front of fraction

a=-1/6

For the slope to be 12, the value of a must be - 16.

Subchapter links

Lesson Check p.193

Practice and Problem-Solving Exercises p.194-196

Standardized Test Prep p.196

Mixed Review p.196