Sign In
| 15 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Analyze the graphs of different linear functions. Do these lines have anything in common?
When trying to find similarities between lines, the first group of lines all have the same y-intercept, while the second group of lines have the same slope. These two characteristics can be used to write an equation of any line.
A linear equation or linear function can be written in the following form called the slope-intercept form.
y=mx+b
In this form, m is the slope and b is the y-intercept. These are the general characteristics or parameters of the line. They determine the steepness and the position of the line on the coordinate plane. Consider the following graph.
This line has a slope of 2 and a y-intercept of 1. The equation of the line can be written in slope-intercept form using these values.
Consider the given linear equation that represents the relation between two variables x and y. Determine whether the equation is written in slope-intercept form.
Tiffaniqua is driving from her home in New York to visit her sister, who lives in Springfield, Missouri. On the first day of the trip, she traveled 250 miles to Washington DC to pick up her friend Maya.
Next, by using the slope, the second point on the line can be determined. Since the slope is 350, move 1 unit right and 350 units up from the first point, then plot the new point.
Finally, by drawing the line through the two plotted points, the graph of the equation can be completed.
Note that since m and d represent the number of miles and days, respectively, they cannot have negative values. This is why the line is only drawn in the first quadrant and is actually a ray.
Next, determine the x-coordinate of that point on the line.
From the graph it can be concluded that Tiffaniqua passed the mark of 1200 miles on the second day of traveling together with Maya. Since on the first day Tiffaniqua traveled 250 miles alone to pick up Maya, the second day of traveling together with Maya is her third day of travel in total.
Tiffaniqua's car broke down right after she arrived at her sister's house, so Tiffaniqua decided to rent a new car while visiting her sister. The rental company charges a one-time insurance fee of $20 and an additional $4 per hour.
Next, the slope 4 will be used to locate a second point. In order to plot this point, move 1 unit right and 4 units up. Points on the line can also be plotted by using multiples of the slope — in this case, for example, 3 units right and 3⋅4=12 units up.
Finally, draw a line through these two points. Note that since c and h represent the cost and number of hours the car is rented, respectively, they can only have non-negative values. This means that the line should only be graphed in the first quadrant.
Now move horizontally to the y-axis to identify the y-coordinate of this point.
The y-coordinate is 48, which means that when renting a car for 7 hours, Tiffaniqua will have to pay a total of $48.
The y-intercept is the y-coordinate of the point where the line crosses the y-axis. This line intercepts the y-axis at (0,-4), which means that the y-intercept is -4.
The evening after Tiffaniqua and Maya arrived at Tiffaniqua's sister's house, the girls decided to pass the evening by putting together puzzles. The number of the remaining puzzle pieces as the girls complete the puzzle is shown in the following graph.
On the diagram, p represents the number of puzzle pieces and t represents time spent completing the puzzle in minutes.
Substitute (-4,1) & (8,4)
a−(-b)=a+b
Add and subtract terms
Calculate quotient
x=8, y=4
Multiply
LHS−2=RHS−2
Rearrange equation
Tiffaniqua really wants to make a dress that she has been dreaming about for a long time. In her sister's town, there is a very famous fabric store, so she decided to go there for the necessary fabric.
Next, use the slope of 0.75 to plot the second point that lies on the line. Note that 0.75 can be rewritten as 43. Therefore, by moving 4 units right and 3 units up, the second point can be located.
Finally, draw a line through the two points to obtain the graph of the equation.
Note that since it is not possible to buy a negative number of yards of fabric, the line should only be drawn for non-negative values of x.
As can be seen, the points indeed lie on the line.
Given a line, two of its points, or its equation in either standard or point-slope form, write an equation in slope-intercept form.
Determine the slope or y-intercept of a line given its graph, two of its points, or its equation, which may or may not be written in slope-intercept form.
We are asked to find the equation of the line that goes through the given points (0,b) and (1,b+m). Recall the form of a linear equation in slope-intercept form. y=slope* x+y-intercept The y-intercept of any line is the point at which the line crosses the y-axis. Its x-coordinate is always 0. We are given the point (0,b). Since its x-coordinate is 0, we can conclude that b is the y-intercept. y=slope* x+ b Now, let's use the Slope Formula and the given points to find the slope.
Now we have enough information to write a complete equation of the line. y= mx+ b
Let's substitute the point (-1,b-m) into the equation from Part A and check whether it still holds true.
We obtained a true statement as b-m will always equal b-m. Therefore, we know that the point lies on the line no matter the values of b and m.
We are given an equation of a line with an unknown m. To find it, we will substitute the first given point (-3,6) into the equation and solve it for m.
Therefore, the equation of the line is y = 3x + 15. Now, we can substitute the coordinates of the second given point (2b,b) and solve the equation for b.
Therefore, b=-3.
Emily's parents opened an account to help pay for her college expenses. They opened the account with an initial deposit of $4000. They set up weekly automatic deposits of $120 to the account.
Since the weekly deposit is constantly $120, we can model the described situation with a linear equation. y=mx+b In this form, m is the slope and b is the y-intercept. We know that the initial deposit is $4000. Therefore, the equation's constant is b= 4000. Also, we know that the weekly deposit is $120, which means the slope is m= 120. d(t)= 120t+ 4000
Similarly, we can model Emily's expenses by a linear equation. The first week's expenses are $500. Since the first week is represented by t=0, the equation's constant is b= 500. Additionally, we know that the weekly expenses after the first week are $250, which means the slope is m= 250.
w(t)= 250t+ 500
To find B(t)=d(t)-w(t), we have to substitute d(t) and w(t) with the corresponding expressions and simplify.
Each week, d(t) represents the amount of money in the account and w(t) represents the amount of money taken out of the account. This means that B(t) is the amount of money left in the account after t weeks.
To determine whether Emily will run out of money and if so, when, we need to find when B(t)=0.
B(t) equals 0 when t is about 27. This means that during the 27th week, Emily will run out of money.
We are given three points lying on the same line, (3,7), (- 6,1), and (7,p) and asked to find the value of p. To do so, we need to find the equation of the line which passes through the first two points. Then, we will use the x-coordinate 7 of the third point to find its y-coordinate p.
We will write the equation of the line in its slope-intercept form. y=mx+b Here, m is the slope and b the y-intercept. Let's start by finding the slope using the Slope Formula.
The slope of the line is 12. We can partially write its equation. y=1/2x+b To find the y-intercept b, we can substitute either of the given points into this equation. Let's use (1,6).
We can now write the equation of the line. y=1/2x+11/2
To find the value of p, we will use the fact that the line also passes through the point (7,p). Let's substitute 7 and p for x and y, respectively, and solve for p.