Exercise 63 Page 196

The given equation is already in written slope-intercept form. Let's start by identifying the slope. Slope-Intercept Form:& y= mx+b Given Equation:& y= -4ax-10In an equation written in slope-intercept form, m represents the slope. Therefore, we can say that -4a is the slope of the given equation. -4a=m To find the value of a such that the graph of the equation has slope - 23, we should substitute this value for m and solve the above equation for a.

-4a=m

Substitute

m= -2/3

-4a= -2/3

MultEqn

LHS * (-1/4)=RHS* (-1/4)

a=-2/3(1/-4)

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Simplify right-hand side

MultFrac

Multiply fractions

a=-2/-12

RemoveNegFracAndDenom

- a/- b= a/b

a=2/12

ReduceFrac

a/b=.a /2./.b /2.

a=1/6

For the slope to be - 23, the value of a must be 16.