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The slope-intercept form of a linear equation is a very useful way to represent lines. It is easy to understand and use, and it makes it easy to graph lines. If you are ever unsure how to graph a line, the slope-intercept form is a great way to get started. Here are some additional tips for graphing equations in slope-intercept form: If the slope is positive, the line will slant upwards from left to right. If the slope is negative, the line will slant downwards from left to right. The steeper the slope, the more quickly the line will slant. If the y-intercept is positive, the line will cross the y-axis above the origin. If the y-intercept is negative, the line will cross the y-axis below the origin.
| | 15 Theory slides |
| | 11 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Analyze the graphs of different linear functions. Do these lines have anything in common?
Examine the graphs of different linear functions. Are there any similarities between these graphs?
When trying to find similarities between lines, the first group of lines all have the same y-intercept, while the second group of lines have the same slope. These two characteristics can be used to write an equation of any line.
A linear equation or linear function can be written in the following form called the slope-intercept form.
y=mx+b
In this form, m is the slope and b is the y-intercept. These are the general characteristics or parameters of the line. They determine the steepness and the position of the line on the coordinate plane. Consider the following graph.
This line has a slope of 2 and a y-intercept of 1. The equation of the line can be written in slope-intercept form using these values.
y= mx+ b ⇓ y= 2x+ 1Consider the given linear equation that represents the relation between two variables x and y. Determine whether the equation is written in slope-intercept form.
A linear equation or linear function in slope-intercept form has the following form. y=mx+b The slope m and y-intercept b are used to graph the equation. Consider the following function. y=2x-3 There are three steps to follow to graph it.
Tiffaniqua is driving from her home in New York to visit her sister, who lives in Springfield, Missouri. On the first day of the trip, she traveled 250 miles to Washington DC to pick up her friend Maya.
Together they continued traveling 350 miles per day. The number of miles that Tiffaniqua traveled is represented by the following linear equation. m=350d+250 Here, m is the total number of miles traveled and d is the number of days after Tiffaniqua picked up her friend.
y= mx+ b m= 350d+ 250 As seen above, the slope is 350 and the y-intercept is 250. Now, the y-intercept can be used to find the first point. Since the value of the y-intercept is 250, plot (0,250) on a coordinate plane.
Next, by using the slope, the second point on the line can be determined. Since the slope is 350, move 1 unit right and 350 units up from the first point, then plot the new point.
Finally, by drawing the line through the two plotted points, the graph of the equation can be completed.
Note that since m and d represent the number of miles and days, respectively, they cannot have negative values. This is why the line is only drawn in the first quadrant and is actually a ray.
Next, determine the x-coordinate of that point on the line.
From the graph it can be concluded that Tiffaniqua passed the mark of 1200 miles on the second day of traveling together with Maya. Since on the first day Tiffaniqua traveled 250 miles alone to pick up Maya, the second day of traveling together with Maya is her third day of travel in total.
Tiffaniqua's car broke down right after she arrived at her sister's house, so Tiffaniqua decided to rent a new car while visiting her sister. The rental company charges a one-time insurance fee of $20 and an additional $4 per hour.
y=mx+b Here, m is the slope and b is the y-intercept. The hourly rate of the renting company is $ 4, so by multiplying that value by the number of hours h, the total hourly amount of renting the car for h hours can be calculated. 4h Furthermore, by adding a one-time insurance fee of $ 20, the total cost c of renting the car can be found. c= 4h+ 20
Next, the slope 4 will be used to locate a second point. In order to plot this point, move 1 unit right and 4 units up. Points on the line can also be plotted by using multiples of the slope — in this case, for example, 3 units right and 3* 4=12 units up.
Finally, draw a line through these two points. Note that since c and h represent the cost and number of hours the car is rented, respectively, they can only have non-negative values. This means that the line should only be graphed in the first quadrant.
Now move horizontally to the y-axis to identify the y-coordinate of this point.
The y-coordinate is 48, which means that when renting a car for 7 hours, Tiffaniqua will have to pay a total of $48.
The y-intercept b and the slope m of a line must be found to write the equation of the graph of the line in slope-intercept form . y=mx+b Consider the line shown as an example.
There are four steps to writing the equation of this line.
For this line, the rise is 6 and the run is 2. Substitute these values into the formula to calculate the slope of the line. m=6/2 ⇒ m=3
The evening after Tiffaniqua and Maya arrived at Tiffaniqua's sister's house, the girls decided to pass the evening by putting together puzzles. The number of the remaining puzzle pieces as the girls complete the puzzle is shown in the following graph.
On the diagram, p represents the number of puzzle pieces and t represents time spent completing the puzzle in minutes.
y=mx+b However, in this case, instead of x and y, the variables will be t and p, respectively. Use the given graph to determine the values of the slope m and the y-intercept b. To find the y-intercept, locate the point where the line intercepts the y-axis.
The coordinates of the y-intercept are (0,500), so b is equal to 500. This value can be substituted for b in the general equation. p&=mt+ b & ⇓ p&=mt+ 500 To determine the value of the slope, locate a second point on the line and analyze the rise and run between the two points.
As can be seen, for each 10 units to the right, the line goes 100 units down. By dividing both values by 10, it is obtained that for each 1 unit to the right, the line goes 10 units down. 10 units right and 100 units down ⇕ 1 unit right and10 units down The line goes down as it moves to the right, so it has a negative slope. Therefore, m is - 10. By substituting this value for m, the equation of the line can be completed. p&= mt+500 & ⇓ p&= - 10t+500
The slope m and the y-intercept b of a line must be known to write a linear equation in slope-intercept form. y=mx+b When only two points on the line are known, the following four-step method can be used. For example, the equation of the line that passes through the points (- 4,1) and (8,4) will be written.
Substitute ( - 4, 1) & ( 8,4)
a-(- b)=a+b
Add and subtract terms
Calculate quotient
The slope m of the line passing through the two points is 0.25.
x= 8, y= 4
Multiply
LHS-2=RHS-2
Rearrange equation
Therefore, the y-intercept is 2.
Tiffaniqua really wants to make a dress that she has been dreaming about for a long time. In her sister's town, there is a very famous fabric store, so she decided to go there for the necessary fabric.
After choosing the perfect fabric, she asked the shop assistant how much 4 and 6 yards of the fabric would cost. The shop assistant told her that the costs would be $3 and $4.50, respectively. (4,3) and (6,4.5) Tiffaniqua realizes that she may want to make a matching accessory, so she might need more fabric. The cost of the fabric will help her decide which, if any, accessory she wants to make.
Now that the slope is known, 0.75 can be substituted for m into the equation. y= mx+b ⇓ y= 0.75x+b Next, by substituting either of the two given points into the partly completed equation, the y-intercept b can be found. For example, substitute (4,3) and solve for b.
The y-intercept of the line is 0. Now the equation can be completed. y=0.75x+ 0 ⇕ y=0.75x
Next, use the slope of 0.75 to plot the second point that lies on the line. Note that 0.75 can be rewritten as 34. Therefore, by moving 4 units right and 3 units up, the second point can be located.
Finally, draw a line through the two points to obtain the graph of the equation.
Note that since it is not possible to buy a negative number of yards of fabric, the line should only be drawn for non-negative values of x.
As can be seen, the points indeed lie on the line.
Given a line, two of its points, or its equation in either standard or point-slope form, write an equation in slope-intercept form.
Determine the slope or y-intercept of a line given its graph, two of its points, or its equation, which may or may not be written in slope-intercept form.
In this lesson, writing and graphing linear equations written in slope-intercept form were studied. However, in every case a line or an equation was analyzed individually. Now, consider two lines with the same slope on one coordinate plane. What can be said about these pairs of lines?
A straight line written in slope-intercept form has the following characteristics.
What is the equation of the line?
First, let's recall that in slope-intercept form m represents the slope and b represents the y-intercept. y=mx+b We know that the slope is three more units than the y-intercept. This means that we can express the m-value with the following equation. m=b+3 We also know that the line passes through the point (7,5). Let's substitute b+3 for m and (7,5) for x and y, respectively.
Now that we know b, we can also determine m by substituting b= - 2 into the equation for m. m= - 2+3 ⇔ m=1 Finally, we can write the equation of the line. y= 1x+( - 2) ⇕ y=x-2
The square A has an area of 36 square units and the square B has an area of 25 square units. A line passes through the upper right vertices of both squares.
What is the equation of the line?
The area of a square is equal to its side length squared. Therefore, if we call the side length of the larger square s_a and of the smaller one s_b, we can set up the following equations. s_a^2=36 and s_b^2=25 Note that only positive values make sense for s_a and s_b. Taking square roots on both sides of the equations, we get that s_a=6 and s_b=5. We can use these values to determine the coordinates of the two points of intersection of the line and the squares. The first square is both 6 units wide and 6 units high, so its upper right vertex falls at (6,6).
By adding 6+5, we get that (11,5) are the coordinates of the right upper vertex of the smaller square. Let's substitute these two points into the Slope Formula to calculate the slope of the line.
Now, we can write a partial equation of the line. y=mx+b ⇔ y=- 1/5x+b To find the value of the y-intercept b, we can substitute the coordinates of either of the points into this equation and solve it for b. Let's use (6,6).
Finally, we can complete the equation. y=- 15x+36/5