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| 15 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Analyze the graphs of different linear functions. Do these lines have anything in common?
When trying to find similarities between lines, the first group of lines all have the same y-intercept, while the second group of lines have the same slope. These two characteristics can be used to write an equation of any line.
A linear equation or linear function can be written in the following form called the slope-intercept form.
y=mx+b
In this form, m is the slope and b is the y-intercept. These are the general characteristics or parameters of the line. They determine the steepness and the position of the line on the coordinate plane. Consider the following graph.
This line has a slope of 2 and a y-intercept of 1. The equation of the line can be written in slope-intercept form using these values.
Consider the given linear equation that represents the relation between two variables x and y. Determine whether the equation is written in slope-intercept form.
Tiffaniqua is driving from her home in New York to visit her sister, who lives in Springfield, Missouri. On the first day of the trip, she traveled 250 miles to Washington DC to pick up her friend Maya.
Next, by using the slope, the second point on the line can be determined. Since the slope is 350, move 1 unit right and 350 units up from the first point, then plot the new point.
Finally, by drawing the line through the two plotted points, the graph of the equation can be completed.
Note that since m and d represent the number of miles and days, respectively, they cannot have negative values. This is why the line is only drawn in the first quadrant and is actually a ray.
Next, determine the x-coordinate of that point on the line.
From the graph it can be concluded that Tiffaniqua passed the mark of 1200 miles on the second day of traveling together with Maya. Since on the first day Tiffaniqua traveled 250 miles alone to pick up Maya, the second day of traveling together with Maya is her third day of travel in total.
Tiffaniqua's car broke down right after she arrived at her sister's house, so Tiffaniqua decided to rent a new car while visiting her sister. The rental company charges a one-time insurance fee of $20 and an additional $4 per hour.
Next, the slope 4 will be used to locate a second point. In order to plot this point, move 1 unit right and 4 units up. Points on the line can also be plotted by using multiples of the slope — in this case, for example, 3 units right and 3⋅4=12 units up.
Finally, draw a line through these two points. Note that since c and h represent the cost and number of hours the car is rented, respectively, they can only have non-negative values. This means that the line should only be graphed in the first quadrant.
Now move horizontally to the y-axis to identify the y-coordinate of this point.
The y-coordinate is 48, which means that when renting a car for 7 hours, Tiffaniqua will have to pay a total of $48.
The y-intercept is the y-coordinate of the point where the line crosses the y-axis. This line intercepts the y-axis at (0,-4), which means that the y-intercept is -4.
The evening after Tiffaniqua and Maya arrived at Tiffaniqua's sister's house, the girls decided to pass the evening by putting together puzzles. The number of the remaining puzzle pieces as the girls complete the puzzle is shown in the following graph.
On the diagram, p represents the number of puzzle pieces and t represents time spent completing the puzzle in minutes.
Substitute (-4,1) & (8,4)
a−(-b)=a+b
Add and subtract terms
Calculate quotient
x=8, y=4
Multiply
LHS−2=RHS−2
Rearrange equation
Tiffaniqua really wants to make a dress that she has been dreaming about for a long time. In her sister's town, there is a very famous fabric store, so she decided to go there for the necessary fabric.
Next, use the slope of 0.75 to plot the second point that lies on the line. Note that 0.75 can be rewritten as 43. Therefore, by moving 4 units right and 3 units up, the second point can be located.
Finally, draw a line through the two points to obtain the graph of the equation.
Note that since it is not possible to buy a negative number of yards of fabric, the line should only be drawn for non-negative values of x.
As can be seen, the points indeed lie on the line.
Given a line, two of its points, or its equation in either standard or point-slope form, write an equation in slope-intercept form.
Determine the slope or y-intercept of a line given its graph, two of its points, or its equation, which may or may not be written in slope-intercept form.
A straight line written in slope-intercept form has the following characteristics.
First, let's recall that in slope-intercept form m represents the slope and b represents the y-intercept. y=mx+b We know that the slope is three more units than the y-intercept. This means that we can express the m-value with the following equation. m=b+3 We also know that the line passes through the point (7,5). Let's substitute b+3 for m and (7,5) for x and y, respectively.
Now that we know b, we can also determine m by substituting b= - 2 into the equation for m. m= - 2+3 ⇔ m=1 Finally, we can write the equation of the line. y= 1x+( - 2) ⇕ y=x-2
The square A has an area of 36 square units and the square B has an area of 25 square units. A line passes through the upper right vertices of both squares.
The area of a square is equal to its side length squared. Therefore, if we call the side length of the larger square s_a and of the smaller one s_b, we can set up the following equations. s_a^2=36 and s_b^2=25 Note that only positive values make sense for s_a and s_b. Taking square roots on both sides of the equations, we get that s_a=6 and s_b=5. We can use these values to determine the coordinates of the two points of intersection of the line and the squares. The first square is both 6 units wide and 6 units high, so its upper right vertex falls at (6,6).
By adding 6+5, we get that (11,5) are the coordinates of the right upper vertex of the smaller square. Let's substitute these two points into the Slope Formula to calculate the slope of the line.
Now, we can write a partial equation of the line. y=mx+b ⇔ y=- 1/5x+b To find the value of the y-intercept b, we can substitute the coordinates of either of the points into this equation and solve it for b. Let's use (6,6).
Finally, we can complete the equation. y=- 15x+36/5