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| 15 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Analyze the graphs of different linear functions. Do these lines have anything in common?
When trying to find similarities between lines, the first group of lines all have the same y-intercept, while the second group of lines have the same slope. These two characteristics can be used to write an equation of any line.
A linear equation or linear function can be written in the following form called the slope-intercept form.
y=mx+b
In this form, m is the slope and b is the y-intercept. These are the general characteristics or parameters of the line. They determine the steepness and the position of the line on the coordinate plane. Consider the following graph.
This line has a slope of 2 and a y-intercept of 1. The equation of the line can be written in slope-intercept form using these values.
Consider the given linear equation that represents the relation between two variables x and y. Determine whether the equation is written in slope-intercept form.
Tiffaniqua is driving from her home in New York to visit her sister, who lives in Springfield, Missouri. On the first day of the trip, she traveled 250 miles to Washington DC to pick up her friend Maya.
Next, by using the slope, the second point on the line can be determined. Since the slope is 350, move 1 unit right and 350 units up from the first point, then plot the new point.
Finally, by drawing the line through the two plotted points, the graph of the equation can be completed.
Note that since m and d represent the number of miles and days, respectively, they cannot have negative values. This is why the line is only drawn in the first quadrant and is actually a ray.
Next, determine the x-coordinate of that point on the line.
From the graph it can be concluded that Tiffaniqua passed the mark of 1200 miles on the second day of traveling together with Maya. Since on the first day Tiffaniqua traveled 250 miles alone to pick up Maya, the second day of traveling together with Maya is her third day of travel in total.
Tiffaniqua's car broke down right after she arrived at her sister's house, so Tiffaniqua decided to rent a new car while visiting her sister. The rental company charges a one-time insurance fee of $20 and an additional $4 per hour.
Next, the slope 4 will be used to locate a second point. In order to plot this point, move 1 unit right and 4 units up. Points on the line can also be plotted by using multiples of the slope — in this case, for example, 3 units right and 3⋅4=12 units up.
Finally, draw a line through these two points. Note that since c and h represent the cost and number of hours the car is rented, respectively, they can only have non-negative values. This means that the line should only be graphed in the first quadrant.
Now move horizontally to the y-axis to identify the y-coordinate of this point.
The y-coordinate is 48, which means that when renting a car for 7 hours, Tiffaniqua will have to pay a total of $48.
The y-intercept is the y-coordinate of the point where the line crosses the y-axis. This line intercepts the y-axis at (0,-4), which means that the y-intercept is -4.
The evening after Tiffaniqua and Maya arrived at Tiffaniqua's sister's house, the girls decided to pass the evening by putting together puzzles. The number of the remaining puzzle pieces as the girls complete the puzzle is shown in the following graph.
On the diagram, p represents the number of puzzle pieces and t represents time spent completing the puzzle in minutes.
Substitute (-4,1) & (8,4)
a−(-b)=a+b
Add and subtract terms
Calculate quotient
x=8, y=4
Multiply
LHS−2=RHS−2
Rearrange equation
Tiffaniqua really wants to make a dress that she has been dreaming about for a long time. In her sister's town, there is a very famous fabric store, so she decided to go there for the necessary fabric.
Next, use the slope of 0.75 to plot the second point that lies on the line. Note that 0.75 can be rewritten as 43. Therefore, by moving 4 units right and 3 units up, the second point can be located.
Finally, draw a line through the two points to obtain the graph of the equation.
Note that since it is not possible to buy a negative number of yards of fabric, the line should only be drawn for non-negative values of x.
As can be seen, the points indeed lie on the line.
Given a line, two of its points, or its equation in either standard or point-slope form, write an equation in slope-intercept form.
Determine the slope or y-intercept of a line given its graph, two of its points, or its equation, which may or may not be written in slope-intercept form.
Write an equation of the line with the given slope and y-intercept.
Lines written in slope-intercept form follow a certain format. y= mx+ b In this form, m is the slope and b is the y-intercept. We know that the slope is 3 and the y-intercept is 8. By substituting m= 3 and b= 8 into this equation, we can write the equation of the line in slope-intercept form. y= 3x+ 8
Here, we are given that the slope is - 1 and the y-intercept is 7. Similarly to Part A, let's substitute these values for m and b, respectively. y= mx+ b ⇓ y= - 1x+ 7 Since the value of the slope, which is also a coefficient before x, is - 1, we can omit writing 1 and leave only the negative sign. y=- 1x+7 ⇓ y=- x+7
This time, the slope is 23 and the y-intercept is - 11. Let's substitute m= 23 and b= - 11 into the general equation in slope-intercept form. y= mx+ b ⇓ y= 2/3x+( - 11) Adding a negative number is equivalent to subtracting the absolute value of that number. Using this piece of information, we can rewrite the equation of the line. y=2/3x+(- 11) ⇕ y=2/3x-11
Write an equation of the line in slope-intercept form.
Equations written in slope-intercept form follow a specific format. y= mx+ b In this form, m is the slope and b is the y-intercept. We need to identify these values using the graph and the two given points. The y-intercept is the y-coordinate of the point where the line crosses the y-axis.
The function intersects the y-axis at (0, 3). This means that the value of b is 3. y= mx+ 3 To find the slope, we will consider the two given points and find the slope m by determining the rise and run of the graph.
Here we have (3,4) as the other given point. Traveling from the y-intercept to this point requires to move 3 steps horizontally in the positive direction and 1 step vertically in the positive direction. rise/run=1/3 ⇔ m= 1/3 Now that we have the slope and the y-intercept, we can write the final equation of the line. y= 1/3x+ 3
In a similar fashion as in Part A, we will use the graph to identify the slope and the y-intercept. To find the y-intercept, identify the y-coordinate of the point where the line crosses the y-axis.
The function intercepts the y-axis at (0, 2). Therefore, the value of b is 2. y= mx+ 2 Next, we can find the slope by considering the two given points. Look at their locations and determine the rise and run of the graph.
The other given point is (4,1). Traveling from the y-intercept to this point requires to move 4 steps horizontally in the positive direction and 1 step vertically in the negative direction. rise/run=- 1/4 ⇔ m= - 1/4 Now that we have the slope and the y-intercept, we can write the final equation of the line. y= - 1/4x+ 2
Again, first let's find the slope and the y-intercept. We can identify the y-intercept by looking for the point where the line crosses the y-axis.
The function intercepts the y-axis at (0, 0). This means that the value of b is 0. y= mx+ 0 ⇓ y= mx Now, find the slope by analyzing the locations of the two given points.
The other given point is (- 3,3). Moving from the y-intercept to this point requires to move 3 steps horizontally in the negative direction and 3 step vertically in the positive direction. rise/run=3/- 3 ⇔ m= - 1 Now that we have the slope and the y-intercept, we can write the final equation of the line. y= - 1x ⇓ y=- x
Write an equation of the line that passes through the given points.
An equation in slope-intercept form follows a specific format. y= mx+ b Here, m is the slope and b is the y-intercept. First, we can use the given points to calculate m. To do this, we will substitute their coordinates into the Slope Formula.
A slope of - 2 means that for every 1 horizontal step to the right, the line goes 2 vertical steps down. Now that we know the slope, we can substitute it into the equation in slope-intercept form. y= - 2x+ b Next, we need to find the y-intercept represented by b. Note that one of the given points, (0, 9), has 0 as its x-coordinate. This indicates that it lies on the y-axis. Since the line crosses the y-axis at this point, we can conclude that the y-intercept is 9. y= - 2x+ 9
Similarly to Part A, to write an equation of the line that passes through the given points, we need to find the slope and the y-intercept. First, we can calculate the slope by substituting the points into the Slope Formula.
A slope of 5 means that for every 1 horizontal step to the right, the line goes 5 vertical steps up. Now that we know the slope, we can substitute it into the equation in slope-intercept form. y= 5x+ b Let's find the y-intercept represented by b. We can notice that one of the given points, (0, - 4), has 0 as its x-coordinate. This means that the point lies on the y-axis. Therefore, we can conclude that the y-intercept is - 4. y= 5x+( - 4) ⇓ y=5x-4
Again, to write an equation of the line, we need to find the slope and the y-intercept. Let's start by calculating the slope by substituting the points into the Slope Formula.
A slope of 0 means that for every 1 horizontal step in the positive direction, we take 0 vertical steps. Therefore, we have a horizontal line. Now that we know the slope, we can write a partial version of the equation. y= 0x+ b ⇓ y= b To complete the equation, we also need to substitute the y-intercept, b. We can see that one of our given points, (0, - 5), lies on the y-axis. Therefore, the y-intercept is - 5. y= - 5
Emily is doing a 6500-piece puzzle. She has already placed 225 pieces. She places 10 more pieces for each minute that passes.
Emily is working on a 6500-piece puzzle and already placed 225 pieces. Every minute she is able to place 10 more pieces. We need to represent this information in slope-intercept form. y=mx+b In this form, m is the slope and b is the y-intercept. Let x represent the number of minutes that have passed. Then 10x is the number of pieces that are placed after x minutes. Already placed: 225 pieces Newly placed: 10x pieces If we find the sum of these two terms, we obtain y, the total number of pieces placed. y= 10x+ 225 This equation models the number of pieces placed by Emily.
Since x represents how long Emily was placing the puzzles in minutes, we need to first convert 1 hour into minutes. There are 60 minutes in an hour, so by substituting 60 for x, we can find how many pieces Emily will have placed after 60 more minutes have passed.
After 60 minutes, Emily will have placed 825 pieces in total.
Zain is driving a remote control car at a constant speed. They start the timer when the car is 7 feet away from them. After 3 seconds, the car is 25 feet away.
Let t be the time in seconds that the car has been driving, and let d be the distance of the car from Zain. Since the equation should be written in slope-intercept form, it will have the following form. d= mt+ b Here, m is the slope and b is the d-intercept. We know that the car drives at a constant speed and that the timer starts when the car is 7 feet away from Zain. In other words, when t=0 and d=7. ( t, d) ⇓ ( 0, 7) We can conclude that the line passes through the point (0,7). Since its t-coordinate is 0, this point lies on a d-axis and is the d-intercept. Therefore, b= 7. d= mt+ 7 To write a complete equation of the line, we need to determine the slope of the line m. It is given that after 3 seconds the car is 25 feet away from Zain. This means the line passes through the point (3,25). By substituting this point into the equation, we can solve it for m.
Now that we know the slope of the line, we can write the complete equation. d=6t+7
By substituting t=11 into the equation from Part A, we can determine the distance between the car and Zain after 11 seconds.
After 11 seconds the car is 73 feet away from Zain.