McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Simplifying Radical Expressions
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Exercise 7 Page 248

For radical expressions where the exponent of a variable inside the radical is even and the simplified expression has an even exponent, absolute value symbols are not needed.

2x^2y^3sqrt(15y)

Practice makes perfect
Before we attempt to simplify the given radical expression, let's consider one of the more difficult parts of correctly simplifying radicals. When the exponent of a variable inside the radical is even and the simplified expression for that variable has an odd exponent, we need to use absolute value symbols. ll sqrt(x^2)= |x| & sqrt(x^3)=x sqrt(x) sqrt(x^4)=x^2 & sqrt(x^6)=|x^3| This is because we do not want the result to be negative — the range of a square root function is all real numbers greater than or equal to 0. Now, consider the given radical expression. sqrt(60x^4y^7) The exponent of x is even and, in the simplified expression, this variable will have an even exponent. Therefore, when we remove x from the radical, we will not need absolute value symbols. The exponent of y is odd, so we will not need absolute value symbols when we remove y from the radical.
sqrt(60x^4y^7)
sqrt(15* 4x^4y^7)
sqrt(15*2^2x^4y^7)
sqrt(15*2^2x^4y^((6+1)))
sqrt(15*2^2x^4y^6y^1)
sqrt(15*2^2x^4y^6y)
Now that we have simplified the factors as much as possible, let's recall the Product Property of Square Roots. sqrt(a* b)=sqrt(a) * sqrt(b), for a≥ 0,b≥ 0 Let's use this property to simplify our expression even further.
sqrt(15*2^2x^4y^6y)
sqrt(15)* sqrt(2^2)*sqrt(x^4)*sqrt(y^6)*sqrt(y)
sqrt(15)* sqrt(2^2)*sqrt(x^(2(2)))*sqrt(y^(3(2)))*sqrt(y)
sqrt(15)* sqrt(2^2)*sqrt((x^2)^2)*sqrt((y^3)^2)*sqrt(y)
sqrt(15)* 2* x^2* y^3* sqrt(y)
2x^2y^3sqrt(15)sqrt(y)
2x^2y^3sqrt(15y)