McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Simplifying Radical Expressions
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Exercise 36 Page 248

Practice makes perfect
a

We are given a function that models the velocity v of water being pumped into the air.

v=sqrt(2hg) In this function, h is the maximum height of the water and g is the acceleration due to gravity. We are asked to solve this function for h. Because we have a square root, we will start by squaring both sides of the function.

v=sqrt(2hg)
v^2=(sqrt(2hg))^2
v^2=2hg
v^2/2g=h
h=v^2/2g

b

We are asked if a pump with a velocity of 70 feet per second will propel water 80 feet into the air. Let's first find the maximum height of the water propelled by this pump. Recall that g is 32ft/s^2. Therefore, we will substitute v= 70 and g= 32 into the function we found in Part A.

h=v^2/2g
h=70^2/2( 32)
â–¼
Evaluate right-hand side
h=70^2/64
h=4900/64
h=76.5625
h≈ 76.6

The pump will propel water to a maximum height of 76.6 feet. Therefore, it will not meet the department's needs.

c

Proceeding in the same way we did in Part B, let's substitute v= 77 and g= 32 into the equation from Part A and simplify.

h=v^2/2g
h=77^2/2( 32)
â–¼
Evaluate right-hand side
h=77^2/64
h=5929/64
h=92.640625
h≈ 92.6

The pump will propel water to a maximum height of 92.6 feet. Therefore, it will meet the needs of the department.