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Start by squaring both sides of the function.
Substitute 70 for v and 32 for g into the function we found in Part A.
Substitute 77 for v and 32 for g into the function we found in Part A.
h=v^2/2g
No, see solution.
Yes, see solution.
We are given a function that models the velocity v of water being pumped into the air.
LHS^2=RHS^2
( sqrt(a) )^2 = a
.LHS /2g.=.RHS /2g.
Rearrange equation
We are asked if a pump with a velocity of 70 feet per second will propel water 80 feet into the air. Let's first find the maximum height of the water propelled by this pump. Recall that g is 32ft/s^2. Therefore, we will substitute v= 70 and g= 32 into the function we found in Part A.
The pump will propel water to a maximum height of 76.6 feet. Therefore, it will not meet the department's needs.
Proceeding in the same way we did in Part B, let's substitute v= 77 and g= 32 into the equation from Part A and simplify.
The pump will propel water to a maximum height of 92.6 feet. Therefore, it will meet the needs of the department.