McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Simplifying Radical Expressions
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Exercise 45 Page 249

To rationalize a fraction with a binomial denominator, we multiply the numerator and denominator of the fraction by the conjugate of the denominator.

6sqrt(3)+9sqrt(2)/2

Practice makes perfect

To rationalize a fraction with a binomial denominator, we multiply the numerator and denominator of the fraction by the conjugate of the denominator. Let's first rewrite the denominator. 3sqrt(3)/-2+sqrt(6) ⇔ 3sqrt(3)/sqrt(6)-2We find the conjugate by changing the sign of the second term of the expression.

Binomial Conjugate
a + b a - b
a - b a + b

In this case, the conjugate of the denominator is sqrt(6)+2.

3sqrt(3)/sqrt(6)-2
3sqrt(3)(sqrt(6)+2)/(sqrt(6)-2)(sqrt(6)+2)
â–¼
Distribute 3sqrt(3)
3sqrt(3)* sqrt(6)+6sqrt(3)/(sqrt(6)-2)(sqrt(6)+2)
3sqrt(3* 6)+6sqrt(3)/(sqrt(6)-2)(sqrt(6)+2)
3sqrt(18)+6sqrt(3)/(sqrt(6)-2)(sqrt(6)+2)
3sqrt(18)+6sqrt(3)/(sqrt(6))^2-2^2
â–¼
Calculate power
3sqrt(18)+6sqrt(3)/6-2^2
3sqrt(18)+6sqrt(3)/6-4
â–¼
Simplify root
3sqrt(9* 2)+6sqrt(3)/6-4
3sqrt(9)sqrt(2)+6sqrt(3)/6-4
3(3)sqrt(2)+6sqrt(3)/6-4
9sqrt(2)+6sqrt(3)/6-4
9sqrt(2)+6sqrt(3)/2
6sqrt(3)+9sqrt(2)/2