McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Quadratic Inequalities
Continue to next subchapter

Exercise 33 Page 211

Solve the related quadratic equation, plot the solutions on a number line, and test a value from each interval.

{ x| 4 < x < 5 }

Practice makes perfect

To solve the quadratic inequality algebraically, we will follow three steps.

  1. Solve the related quadratic equation.
  2. Plot the solutions on a number line.
  3. Test a value from each interval to see if it satisfies the original inequality.

Step 1

We will start by solving the related equation. x^2-9x=- 20 ⇔ 1x^2+( - 9)x+ 20=0We see above that a= 1, b= - 9, and c= 20. Let's substitute these values into the Quadratic Formula to solve the equation.
x=- b±sqrt(b^2-4ac)/2a
x=- ( - 9)±sqrt(( - 9)^2-4( 1)( 20))/2( 1)
â–Ľ
Simplify right-hand side
x=9±sqrt((- 9)^2-4(1)(20))/2(1)
x=9±sqrt(81-4(1)(20))/2(1)
x=9±sqrt(81-80)/2
x=9±sqrt(1)/2
x=9 ± 1/2
Now we can calculate the first solution using the positive sign and the second solution using the negative sign.
x=9 ± 1/2
x=9 + 1/2 x=9 - 1/2
x= 10/2 x= 8/2
x=5 x=4

Step 2

The solutions of the related equation are 5 and 4. Let's plot them on a number line. Since the original is a strict inequality, the points will be open.

Step 3

Finally, we must test a value from each interval to see if it satisfies the original inequality. Let's choose a value from the first interval, x < 4. For simplicity, we will choose x=0.
x^2-9x < - 20
0^2-9( 0)? <- 20
â–Ľ
Simplify left-hand side
0-9(0)? <- 20
0-0? <- 20
0 ≮ - 20 *
Since x=0 did not produce a true statement, the interval x < 4 is not part of the solution. Similarly, we can test the other two intervals.
Interval Test Value Statement Is It Part of the Solution?
4< x < 5 4.5 - 20.25 < - 20 âś“ Yes
x > 5 10 10 ≮ - 20 * No

We can now write the solution set and show it on a number line. { x| 4 < x < 5 } or (4, 5)