Sign In
| 8 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
An absolute value inequality in two variables is an inequality that contains an absolute value expression and shows the relationship between two variables. If the relationship is linear, then the inequality is similar to the equation of an absolute value function. Example [-0.8em] Equation: y = |8x-3|+2 Inequality: y ≤ |8x-3|+2 While the graph of an absolute value equation is a V-shaped graph, the graph of a two-variable absolute value inequality is a region. When graphing a two-variable absolute value inequality, its boundary line plays an important role.
The boundary line of the inequality can be determined by replacing the inequality symbol with the equals sign. Inequality: & y-3 > |3x-6| Boundary Line: & y-3 = |3x-6| The graph of the boundary line can be drawn using a table of values. To make calculations easy, first y will be isolated. y-3 = |3x-6| ⇕ y=|3x-6|+3 Now some points on the boundary line can be found.
x | y=|3x-6|+3 | y |
---|---|---|
0 | y=|3( 0)-6|+3 | 9 |
1 | y=|3( 1)-6|+3 | 6 |
2 | y=|3( 2)-6|+3 | 3 |
3 | y=|3( 3)-6|+3 | 6 |
4 | y=|3( 4)-6|+3 | 9 |
Plot the points and draw the boundary line. Since the given inequality is strict, the boundary line will be dashed.
x= 0, y= 0
Zero Property of Multiplication
Subtract terms
|-6|=6
The test point is not a solution, so the region that does not contain the test point — inside the V-shaped graph — represents the solution set for the inequality. Finally, the appropriate region can be shaded.
Analyze the graph of the given absolute value inequality in two variables to determine the proper inequality symbol.
Dylan writes an absolute value equation in two variables for the shape of a mirror. y-4 = - |5/2x+5| He knows that only the outside of the mirror is reflective.
LHS+4=RHS+4
a = 2* a/2
Factor out 5/2
|a* b|= |a| * |b|
|5/2|=5/2
a=- (- a)
x | - 5/2|x+2| + 4 | y = -5/2 |x+2 | + 4 |
---|---|---|
- 4 | - 5/2| - 4+2| + 4 = - 1 | - 1 |
- 3 | - 5/2| - 3+2| + 4 = 1.5 | 1.5 |
- 2 | - 5/2| - 2+2| + 4 = 4 | 4 |
- 1 | - 5/2| - 1+2| + 4 = 1.5 | 1.5 |
0 | - 5/2| 0+2| + 4 = - 1 | - 1 |
Finally, plot the points and draw the absolute value equation.
As can be seen, the mirror has a V-shape with a vertex of (- 2,4) in the coordinate plane.
The shaded region represents the y-values greater than - | 52x +5 |+4. The inequality symbol will be strict because the graph of the mirror is not part of the solution set. Inequality: y > - |5/2x+5 | + 4 In this example, the mirror represents the boundary line of the inequality, the spherical light source represents a test point that satisfies the inequality, and the shaded region represents the graph of the inequality.
Ignacio buys an antique object at an auction. He plans to sell it in a few years. He describes the value of the object y (in thousands dollars) after x years as follows. y = 0.4 |x-4| + 3 He is also willing to sell the object at any time for any price greater than or equal to the value found by the above equation.
0.4|x-4|+3 If Ignacio can find someone who is ready to pay greater than or equal to the amount after x years, the object is sold. Therefore, the following inequality will describe the situation. y ≥ 0.4|x-4|+3 To graph this absolute value inequality, its boundary line will be drawn first. To do so, make a table of values for y=0.4|x-4|+3. Note that since x represents the number of years, it cannot be negative.
x | y=0.4|x-4|+3 | y |
---|---|---|
0 | y=0.4| 0-4|+3 | 4.6 |
2 | y=0.4| 2-4|+3 | 3.8 |
4 | y=0.4| 4-4|+3 | 3 |
6 | y=0.4| 6-4|+3 | 3.8 |
8 | y=0.4| 8-4|+3 | 4.6 |
Plot the points and draw the boundary line. Since the inequality is non-strict, the boundary line will be solid. Note that only positive values of x and y makes sense in the context of the situation.
In the same auction, Emily was also interested in the object that Ignacio bought. Emily knows that Ignacio will sell it sooner or later. The maximum amount of money Emily can allocate to buy Ignacio's object is represented by the following graph.
To write the equation of the boundary line, use the vertex form of an absolute value equation y=a|x-h|+k, where (h,k) is the vertex of the absolute value equation.
On the given graph, x represents the years after the auction and y represents the price of the object in thousands of dollars. Since Emily can allocate any amount less than $3800 for the object 4 years after the auction, these values correspond to point (4,3.8), which is the vertex of the boundary line.
x= 10, y= 5
Subtract term
|6|=6
LHS-3.8=RHS-3.8
.LHS /6.=.RHS /6.
Rearrange equation
less than,<. Boundary Line: & y = 0.2|x-4|+3.8 Inequality:& y < 0.2|x-4|+3.8
When absolute value inequalities in two variables are drawn on the same coordinate plane, they might intersect. The region where the graphs of the inequalities intersect represents the solutions that satisfy both inequalities. Consider the following absolute value inequalities. Inequality I: & y ≥ 0.4|x-4|+3 Inequality II: & y < 0.2|x-4|+3.8 There is a small region where the graphs of these inequalities intersect.
Any point in this region is the solution to both inequalities. In the context of the last two examples, Ignacio and Emily can make a deal as long as the values stay in that region.
Which graph represents the solution set of the absolute value inequality y ≥ |3x-12| ?
We will follow three steps to graph the given absolute value inequality.
The boundary line of an inequality can be determined by replacing the inequality symbol with an equal sign. Inequality & Boundary Line y ≥ |3x-12| & y = |3x-12| Notice that the equation of the boundary line is an absolute value equation. Let's rewrite it in vertex form to find its vertex. y = |3x-12| ⇓ y = 3|x- 4|+ 0 Its vertex is ( 4, 0). The graph of the boundary line should be symmetric about the line x=4. To graph the boundary line, we can make a table of values using some x-values greater and less than 4.
x | |3x-12| | y = |3x-12| |
---|---|---|
2 | |3( 2)-12| | 6 |
3 | |3( 3)-12| | 3 |
4 | |3( 4)-12| | 0 |
5 | |3( 5)-12| | 3 |
6 | |3( 6)-12| | 6 |
We now plot the points and draw the boundary line. Since the inequality is non-strict, the boundary line will be solid.
In order to decide which part of the plane to shade, we can test a point which is not on the boundary line. Let's test the point ( 0, 0).
If the point satisfies the inequality, we shade the region that contains the point. Otherwise, we shade the region that does not contain the point. Let's substitute the test point into the given inequality.
Since the point does not satisfy the inequality, it is not a solution to the inequality.
We will shade the region that does not contain the point because the test point is not a solution.
We can see that Graph A is the same as the graph we drew.
Which graph represents the solution set of the absolute value inequality y < |0.75x|+2 ?
We will follow three steps to graph the given absolute value inequality.
The boundary line of an inequality can be determined by replacing the inequality symbol with an equal sign. Inequality & Boundary Line y < |0.75x|+2 & y = |0.75x|+2 Notice that the equation of the boundary line is an absolute value equation. Let's rewrite it in vertex form to find its vertex. y = |0.75x|+2 ⇓ y = 0.75|x- 0|+ 2 Its vertex is ( 0, 2). The graph of the boundary line should be symmetric about the y-axis. To graph the boundary line, we can make a table of values using some x-values below and above 0.
x | |0.75x|+2 | y = |0.75x|+2 |
---|---|---|
- 4 | |0.75( - 4)|+2 | 5 |
0 | |0.75( 0)|+2 | 2 |
4 | |0.75( 4)|+2 | 5 |
We now plot the points and draw the boundary line. Since the inequality is strict, the boundary line will be dashed.
In order to decide which part of the plane to shade, we can test a point which is not on the boundary line. Let's test the point ( 0, 0).
If the point satisfies the inequality, we shade the region that contains the point. Otherwise, we shade the region that does not contain the point. Let's substitute the test point into the given inequality.
Since the point satisfies the inequality, it is a solution to the inequality.
We will shade the region that contains the point because the test point is a solution.
This graph matches with the graph in C.
Which graph represents the solution set of the absolute value inequality y+ 10 > 5 | 14x+2|?
We will follow three steps to graph the given absolute value inequality.
In this case, we will first isolate the y-variable.
The boundary line of an inequality can be determined by replacing the inequality symbol with an equal sign. Inequality & Boundary Line y > 5 |1/4x+2|-10 & y = 5 |1/4x+2|-10 Notice that the equation of the boundary line is an absolute value equation. Let's rewrite it in vertex form to find its vertex.
We can now identify the vertex. y = 5/4|x+8|-10 ⇓ y = 5/4|x-( - 8)|+ ( - 10) Its vertex is ( - 8, - 10). Therefore, the graph of the boundary line should be symmetric about the line x=- 8. To graph the boundary line, we can make a table of values using some x-values below and above - 8.
x | 5/4|x+8|-10 | y=5/4|x+8|-10 |
---|---|---|
- 16 | 5/4| - 16+8|-10 | 0 |
- 8 | 5/4| - 8+8|-10 | - 10 |
0 | 5/4| 0+8|-10 | 0 |
We now plot the points and draw the boundary line. Since the inequality is strict, the boundary line will be dashed.
In order to decide which part of the plane to shade, we can test a point which is not on the boundary line. Let's test the point ( - 8, 0).
If the point satisfies the inequality, we shade the region that contains the point. Otherwise, we shade the region that does not contain the point. Let's substitute the test point into the given inequality.
Since the point satisfies the inequality, it is a solution to the inequality.
We will shade the region that contains the point because the test point is a solution.
This graph matches with the graph in option B.
Write an inequality for the given graph.
To write an inequality for the graph, we will follow two steps.
Let's get started by focusing on the boundary line.
We see that the vertex of the boundary line is (- 4,0). Recall the vertex form of an absolute value equation whose vertex is at (h,k). y = a|x-h|+k Since the vertex of the boundary line is ( - 4, 0), the corresponding values can be substituted and the expression simplified.
We can substitute a point on the boundary line, different than the vertex, to find the value of a. We know that (- 6,2) lies on the boundary line. Let's substitute these values into our equation and solve for a!
We can now write the equation of the boundary line. y = 1|x+4| ⇔ y = |x+4|
Now that we have the equation of the boundary line, we will determine the inequality symbol.
Since the boundary line is dashed, the inequality will be strict, meaning that it is either < or >. The shaded region is below the boundary line. That is, the y-values are less than |x+4|. Therefore, the inequality symbol should be <. Boundary Line: & y = |x+4| Inequality:& y < |x+4|
We can check our answer by substituting a point in the shaded region into our function and simplifying. If the solution is true, we know our answer is correct. Let's try (- 3,- 2).
We can conclude that the solution set of the inequality is the given graph.
Write an inequality for the given graph.
To write an inequality for the graph, we will follow two steps.
Let's get started by focusing on the boundary line.
We see that the vertex of the boundary line is (5,- 1). Recall the vertex form of an absolute value equation whose vertex is at (h,k). y = a|x-h|+k Since the vertex of the boundary line is ( 5, - 1), the corresponding values can be substituted.
We can substitute a point on the boundary line to find the value of a. Let's use (0,- 5).
We can now write the equation of the boundary line. y = - 0.8|x-5|-1
Now that we have the equation of the boundary line, we will determine the inequality symbol.
Since the boundary line is solid, the inequality will be non-strict, meaning that it is either ≤ or ≥. The shaded region is above the boundary line. That is, the y-values are greater than or equal to |x+4|. Therefore, the inequality symbol should be ≥. Boundary Line: & y = - 0.8|x-5|-1 Inequality:& y ≥ - 0.8|x-5|-1
We can check our answer by substituting a point in the shaded region. If the inequality is correct, then it will produce a true statement. Let's try (0,0).
We can conclude that the solution set of the inequality is the given graph.