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Solve the related quadratic equation, plot the solutions on a number line, and test a value from each interval.
{ x| - 3 ≤ x ≤ 7 }
To solve the quadratic inequality algebraically, we will follow three steps.
We will start by solving the related equation.
x^2-4x=21 ⇔ 1x^2+( - 4)x+( - 21)=0
Substitute values
Calculate root
Now we can calculate the first root using the positive sign and the second root using the negative sign.
| x=4± 10/2 | |
|---|---|
| x=4+ 10/2 | x=4- 10/2 |
| x=4/2 + 10/2 | x=4/2 - 10/2 |
| x=7 | x=- 3 |
The solutions of the related equation are - 3 and 7. Let's plot them on a number line. Since the original is not a strict inequality, the points will be closed.
Finally, we must test a value from each interval to see if it satisfies the original inequality. Let's choose a value from the first interval, x ≤ - 3. For simplicity, we will choose x=- 4.
Since x=- 4 did not produce a true statement, the interval x ≤ - 3 is not part of the solution. Similarly, we can test the other two intervals.
| Interval | Test Value | Statement | Is It Part of the Solution? |
|---|---|---|---|
| - 3 ≤ x ≤ 7 | 0 | 0 ≤ 21 ✓ | Yes |
| x ≥ 7 | 10 | 60 ≰ 21 * | No |
We can now write the solution set and show it on a number line. { x| - 3 ≤ x ≤ 7 } or [- 3, 7]