McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Quadratic Inequalities
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Exercise 23 Page 211

Find the roots and use them to graph the related function.

{ x| x < - 1.42 or x > 8.42 }

Practice makes perfect
We will start by rearranging the given quadratic inequality. 0 > - x^2+7x+12 ⇔ - x^2+7x+12 < 0 We will now sketch the related quadratic function. To do so, we first need to identify the values of a, b, and c. y= - 1x^2 + 7x + 12 We see that a= - 1, b= 7, and c= 12. Let's substitute these values into the Quadratic Formula to find the roots of - x^2+7x+12=0.
x=- b±sqrt(b^2-4ac)/2a
x=- 7±sqrt(( 7)^2-4( - 1)( 12))/2( - 1)
Simplify right-hand side
x=- 7±sqrt(49-4(- 1)(12))/2(- 1)
x=- 7±sqrt(49+48)/- 2
x=- 7±sqrt(97)/- 2
Now we can calculate the first root using the positive sign and the second root using the negative sign.
x=- 7±sqrt(97)/- 2
x=- 7 + sqrt(97)/- 2 x=- 7 - sqrt(97)/- 2
x=7/2-sqrt(97)/2 x=7/2+sqrt(97)/2
x≈ - 1.42 x≈ 8.42

The solution of the given quadratic inequality, - x^2+7x+12 < 0, consists of x-values for which the graph of the related quadratic function lies below the x-axis. The graph opens downward, since a= - 1 is less than zero.

We see that the graph lies below the x-axis at about x < - 1.42 and x > 8.42. { x| x < - 1.42 or x > 8.42 } ⇕ (- ∞, - 1.42) ⋃ (8.42, ∞ )

Showing Our Work

Drawing the parabola using roots and vertex
We already know the roots, which are around - 1.42 and 8.42. To draw the graph, we will find the vertex, (- b2a,f(- b2a)). Let's start by calculating its x-coordinate. To do so, we will substitute a= - 1 and b= 7 into - b2a.
- b/2a
- 7/2( - 1)
- 7/- 2
7/2
Finally, to find the y-coordinate of the vertex, we will substitute 72 for x in the related function y=- x^2+7x+12.
y=- x^2+7x+12
y=- ( 7/2 )^2+7 ( 7/2 ) +12
Simplify right-hand side
y=- ( 49/4 )+7( 7/2 ) +12
y=- ( 49/4 )+(7)7/2+12
y=- 49/4 +49/2+12
y=- 49/4 +98/4+12
y=- 49/4 +98/4+48/4
y=97/4
y=24 14
The vertex is ( 72,24 14 ). This point, along with the roots, is helpful to graph a parabola.