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Solve the related quadratic equation, plot the solutions on a number line, and test a value from each interval.
{ x| - 2.84 < x < 0.84 }
To solve the quadratic inequality algebraically, we will follow three steps.
We will start by solving the related equation.
- 12 = - 5x^2-10x ⇔ 5x^2+ 10x+( - 12)=0
Substitute values
Now we can calculate the first root using the positive sign and the second root using the negative sign.
| x=- 10±sqrt(340)/10 | |
|---|---|
| x=- 10 + sqrt(340)/10 | x=- 10 - sqrt(340)/10 |
| x=- 10/10+sqrt(340)/10 | x=- 10/10-sqrt(340)/10 |
| x≈ 0.84 | x≈ - 2.84 |
The solutions of the related equation are approximately - 2.84 and 0.84. Let's plot them on a number line. Since the original is a strict inequality, the points will be open.
Finally, we must test a value from each interval to see if it satisfies the original inequality. Let's choose a value from the first interval, x < - 2.84. For simplicity, we will choose x=- 4.
Since x=- 4 did not produce a true statement, the interval x < - 2.84 is not part of the solution. Similarly, we can test the other two intervals.
| Interval | Test Value | Statement | Is It Part of the Solution? |
|---|---|---|---|
| - 2.84 < x < 0.84 | 0 | - 12 < 0 ✓ | Yes |
| x > 0.84 | 1 | - 12 ≮ - 15 * | No |
We can now write the solution set and show it on a number line. { x| - 2.84 < x < 0.84 } or (- 2.84, 0.84)