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Solve the related quadratic equation, plot the solutions on a number line, and test a value from each interval.
{ x| x ≤ - 1.58 or x ≥ 1.58 }
To solve the quadratic inequality algebraically, we will follow three steps.
We will start by solving the related equation.
2x^2+4=9 ⇔ 2x^2+ 0x+( - 5)=0
Substitute values
Calculate power
Multiply
Identity Property of Addition
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
a/b=.a /2./.b /2.
Now we can calculate the first root using the positive sign and the second root using the negative sign.
| x=±sqrt(10)/2 | |
|---|---|
| x=sqrt(10)/2 | x=- sqrt(10)/2 |
| x≈ 1.58 | x≈ - 1.58 |
The solutions of the related equation are approximately - 1.58 and 1.58. Let's plot them on a number line. Since the original is not a strict inequality, the points will be closed.
Finally, we must test a value from each interval to see if it satisfies the original inequality. Let's choose a value from the first interval, x ≤ - 1.58. For simplicity, we will choose x=- 2.
Since x=- 2 produced a true statement, the interval x ≤ - 1.58 is a part of the solution. Similarly, we can test the other two intervals.
| Interval | Test Value | Statement | Is It Part of the Solution? |
|---|---|---|---|
| - 1.58 ≤ x ≤ 1.58 | 0 | 4 ≱ 9 * | No |
| x ≥ 1.58 | 2 | 12 ≥ 9 ✓ | Yes |
We can now write the solution set and show it on a number line. { x| x ≤ - 1.58 or x ≥ 1.58 } or (- ∞, - 1.58] ⋃ [1.58, ∞)