5. Quadratic Inequalities
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Identify the coordinates of the vertex.
y=2(x-3)^2-4
The vertex of this parabola has coordinates (3,- 4). This means that we have h=3 and k=- 4. We can use these values to partially write our function. y=a(x-3)^2+(- 4) ⇕ y=a(x-3)^2-4 We can see in the graph that the parabola opens upwards. Therefore, a will be a positive number. To find its value, we will use the given point that is not the vertex.
x= 5, y= 4
Subtract terms
Calculate power
LHS+4=RHS+4
.LHS /4.=.RHS /4.
Rearrange equation