McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Special Right Triangles
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Exercise 30 Page 645

x=3, y=1

Practice makes perfect

Let's divide the given triangle into two right triangles.

We will deal with these triangles one at a time.

Triangle 1

Notice that this is a right triangle with an acute angle that measures 30^(∘). Therefore, by the Triangle Angle Sum Theorem the measure of the third angle must be 60^(∘). We will let the shorter leg of the triangle be s.

We have a 30^(∘)-60^(∘)-90^(∘) triangle. In this type of triangle, the length of the hypotenuse is twice the length of the shorter leg.

2sqrt(3) = 2 * s
â–¼
Solve for s
sqrt(3) = s
s = sqrt(3)

We found that the length of the shorter leg is sqrt(3). Moreover, in a 30^(∘)-60^(∘)-90^(∘) triangle the length of the longer leg is sqrt(3) times the length of the shorter leg. This will let us find the value of x.

x= sqrt(3) * sqrt(3)
x=3

Triangle 2

Our second right triangle has an angle that measures 60^(∘). Therefore, by the Triangle Angle Sum Theorem the measure of the third angle is 30^(∘). Remember, we already know that s=sqrt(3).

This triangle is also a 30^(∘)-60^(∘)-90^(∘) triangle. In this type of triangle, the length of the longer leg is sqrt(3) times the length of the shorter leg. This will let us find the value of y.

sqrt(3)=sqrt(3) * y
1=y
y=1