Start with plotting the given points in a coordinate plane.
(-13,-3)
Practice makes perfect
Let's begin with plotting the given points in a coordinate plane. We can connect these two points with a segment.
Since we know that â–³ XYZ is a right triangle with a right angle at the vertex Y, we can deduct that the vertex X is lying on the horizontal line y=-3.
If △ XYZ is a 45^(∘)-45^(∘)-90^(∘) triangle, then the lengths of segments YZ and YX are equal, as this triangle is isosceles. Let's evaluate the length of YZ.
Therefore the third vertex X is 10 units from Y either in a positive or a negative direction. However, as we are asked to find the coordinates of X in the Quadrant III we will consider only the second case.
