McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
3. Special Right Triangles
Continue to next subchapter

Exercise 45 Page 647

Practice makes perfect
a

We are asked to draw three similar right triangles with a 50^(∘) angle. We will start with △ ABC. Let's start with drawing a segment BA and the angle ∠ B with a measure of 50^(∘).

Since we want ∠ A to be the right angle, we will draw a perpendicular segment that starts in point A and intersects the dashed line we drew. The point of intersection will be the third vertex, C.

Next, we will draw two more triangles △ MNP and △ XYZ. In these triangles ∠ M and ∠ X will be right angles, and ∠ N and ∠ Y will be 50^(∘) angles.

b

In this part, we are asked to complete the given table. To do this, we will measure appropriate sides with a ruler. Let's start with measuring the length of AC.

Next, we will measure the rest of sides in the same way.

Now, we will record these measures in the given table and evaluate the ratios.

Triangle Length Ratio
ABC AC 4.8 BC 6.3 AC/BC 4.8/6.3≈ 0.8
MNP MP 2.4 NP 3.1 MP/NP 2.4/3.1≈ 0.8
XYZ XZ 2.5 YZ 3.3 XZ/YZ 2.5/3.3≈ 0.8

c

Looking at the table, we can see that the ratios are equal for each of the triangles. Therefore, we can assume that in right triangles with a 50^(∘) angle, the ratio of the leg opposite this angle to the hypotenuse is constant.