McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Special Right Triangles
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Exercise 27 Page 645

Notice that the height of the gable divides it into two 45^(∘)-45^(∘)-90^(∘) triangles.

≈22.6 ft.

Practice makes perfect

We are given that Grace wants to decorate the gable of the house, which is an isosceles right triangle, and we are asked to find how many feet of lights Grace will need to cover the gable. Let's notice that the height of the gable divides it into two 45^(∘)-45^(∘)-90^(∘) triangles.

Recall that in 45^(∘)-45^(∘)-90^(∘) triangles the legs are congruent and the hypotenuse is sqrt(2) times the length of a leg. Using this information, we can complete the picture with all the missing measures.

Now we will add the appropriate lengths of the gable below the roof line. 8 sqrt(2)+ 8 sqrt(2)=16sqrt(2)≈22.6 Grace will need approximately 22.6 feet of lights to cover the gable below the roof.