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Popping Volume: about 55.5 cm3/g
Popping Volume: about 44.1 cm3/g
Hot-Oil Popping Domain: 5.35≤x≤21.8
Hot-Oil Popping Range:0≤y≤44.1
Hot-air popping | Hot-oil popping |
---|---|
f(x)=-0.761(x−5.52)(x−22.6) | g(x)=-0.652(x−5.35)(x−21.8) |
The moisture content that maximizes the popping volume corresponds to the x-coordinate of the vertex, and the maximum volume corresponds to the y-coordinate. Let's determine the vertex of y=f(x).
Function | Vertex | |
---|---|---|
f(x)=a(x−p)(x−q) | x=2p+q | y=f(2p+q) |
f(x)=-0.761(x−5.52)(x−22.6) | x=25.52+22.6=14.1 | f(14.1)=55.5 |
The moisture content that maximizes the popping volume is about 14.1%, and the maximum volume is about 55.5 cm3/g.
Function | Vertex | |
---|---|---|
g(x)=a(x−p)(x−q) | x=2p+q | y=f(2p+q) |
g(x)=-0.652(x−5.35)(x−21.8) | x=25.35+21.8=13.6 | f(13.6)=44.1 |
Consequently, the moisture content that maximizes the popping volume is about 13.6%, and the maximum volume is about 44.1 cm3/g.
Let's enter the equations into a graphing calculator by pushing Y= and typing the right-hand side of the equations in the two first rows.
By pushing GRAPH, the calculator will draw the equations.
For the functions to be visible on the screen, re-size the standard window by pushing the WINDOW button. Change the settings to a more appropriate size and then push GRAPH.
Since the variables x and y represent units of measure they have to be greater than zero. Using this and the information obtained in the first two parts, we can state the following conclusions.