Exercise 27 Page 61

To draw the graph of the given quadratic function, written in standard form, we must start by identifying the values of a, b, and c. g(x)=- 1.5x^2+3x+2 ⇔ g(x)=- 1.5x^2+3x+2 We can see that a=- 1.5, b=3, and c=2. Now, we will follow four steps to graph the function.

1. Find the axis of symmetry.
2. Calculate the vertex.
3. Identify the y-intercept and its reflection across the axis of symmetry.
4. Connect the points with a parabola.

   Finding the Axis of Symmetry

   The axis of symmetry is a vertical line with equation x=- b2a. Since we already know the values of a and b, we can substitute them into the formula.
   x=- b/2a

   SubstituteII

   a= - 1.5, b= 3

   x=- 3/2(- 1.5)

   ▼

   Simplify right-hand side

   MultPosNeg

   a(- b)=- a * b

   x=- 3/- 3

   RemoveNegFracAndDenom

   - a/- b= a/b

   x=3/3

   CalcQuot

   Calculate quotient

   x=1
   The axis of symmetry of the parabola is the vertical line with equation x=1.

   Calculating the Vertex

   To calculate the vertex, we need to think of y as a function of x, y=g(x). We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex: ( - b/2a, g( - b/2a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x=1. Thus, the x-coordinate of the vertex is also 1. To find the y-coordinate, we need to substitute 1 for x in the given equation.
   g(x)=- 1.5x^2+3x+2

   Substitute

   x= 1

   g( 1)=- 1.5( 1)^2+3( 1)+2

   ▼

   Simplify right-hand side

   CalcPow

   Calculate power

   g(1)=- 1.5 (1)+3(1)+2

   Multiply

   Multiply

   g(1)=- 1.5+3+2

   AddTerms

   Add terms

   g(1)=3.5
   We found the y-coordinate, and now we know that the vertex is (1,3.5).

   Identifying the y-intercept and its Reflection

   The y-intercept of the graph of a quadratic function written in standard form is given by the value of c. Thus, the point where our graph intercepts the y-axis is (0,2). Let's plot this point and its reflection across the axis of symmetry.

   

   Connecting the Points

   We can now draw the graph of the function. Since a=- 1.5, which is negative, the parabola will open downwards. Let's connect the three points with a smooth curve.