Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
2. Characteristics of Quadratic Functions
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Exercise 64 Page 63

If a quadratic function is written in intercept form f(x)=a(x-p)(x-q), the x-intercepts are p and q.

x-intercepts: - 5 and - 1
Increasing Interval: To the left of x=- 3
Decreasing Interval: To the right of x=- 3
Graph:

Practice makes perfect

We will find the intercepts and the increasing and decreasing intervals of the given quadratic function. Then we will draw the graph to verify our answer.

x-intercepts

Let's rewrite the function to match the intercept form. Then we can identify the x-intercepts, p and q. h(x)=- 5 ( x+5 ) ( x+1 ) ⇕ h(x)= - 5 ( x-( - 5) ) ( x-( - 1) ) The x-intercepts of the given function are p= - 5 and q= - 1.

Increasing and Decreasing Intervals

To describe where the graph is increasing and decreasing, we need to find the axis of symmetry of the parabola. Axis of Symmetry: x = p+q/2 We can find this by substituting - 5 and - 1 for p and q in the above formula.
x = p+q/2
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Substitute values and evaluate
x = - 5+( - 1)/2
x = - 6/2
x=- 6/2
x = - 3

The axis of symmetry is the vertical line x=- 3. Since a= - 5 is less than 0, the parabola opens downwards. Thus, the curve increases to the left of x=- 3 and decreases to the right of x=- 3.

Graph

We already know the x-intercepts of the parabola. Therefore, to draw the graph we only need to find the vertex and join the three points with a smooth curve. Since the axis of symmetry is the line x=- 3, the x-coordinate of the vertex is - 3. To find its y-coordinate, we will substitute - 3 for x in the given equation.
h(x)=- 5(x+5)(x+1)
h(- 3)=- 5(- 3+5)(- 3+1)
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Simplify right-hand side
h(- 3)=- 5(2) (- 2)
h(- 3)=- 5 (- 4)
h(- 3)=20
The vertex of the parabola is (- 3,20). Let's plot the vertex and the intercepts, and connect them with a smooth curve.