Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
2. Characteristics of Quadratic Functions
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Exercise 62 Page 63

If a quadratic function is written in intercept form f(x)=a(x-p)(x-q), the x-intercepts are p and q.

x-intercepts: - 1 and 3
Increasing Interval: To the right of x=1
Decreasing Interval: To the left of x=1
Graph:

Practice makes perfect

We will find the intercepts and the increasing and decreasing intervals of the given quadratic function. Then we will draw the graph to verify our answer.

x-intercepts

Let's rewrite the function to match the intercept form. Then we can identify the x-intercepts, p and q. y=3/4 ( x+1 ) ( x-3 ) ⇕ y= 3/4 ( x-( - 1) ) ( x- 3 ) The x-intercepts of the given function are p= - 1 and q= 3.

Increasing and Decreasing Intervals

To describe where the graph is increasing and decreasing, we need to find the axis of symmetry of the parabola. Axis of Symmetry: x = p+q/2 We can find this by substituting - 1 and 3 for p and q in the above formula.
x = p+q/2
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Substitute values and evaluate
x = - 1+ 3/2
x = 2/2
x = 1

The axis of symmetry is the vertical line x=1. Since a= 34 is greater than 0, the parabola opens upwards. Thus, the curve decreases to the left of x=1 and increases to the right of x=1.

Graph

We already know the x-intercepts of the parabola. Therefore, to draw the graph we only need to find the vertex and join the three point with a smooth curve. Since the axis of symmetry is the line x=1, the x-coordinate of the vertex is 1. To find its y-coordinate, we will substitute 1 for x in the given equation.
y=3/4(x+1)(x-3)
y=3/4(1+1)(1-3)
â–Ľ
Simplify right-hand side
y=3/4 (2) (- 2)
y=3/4(- 4)
y=- 12/4
y=- 3
The vertex of the parabola is (1, - 3). Let's plot the vertex and the intercepts, and connect them with a smooth curve.