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Start by identifying a, b, and c. The minimum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Minimum Value: - 19
Domain: All real numbers
Range: y ≥ - 19
Decreasing Interval: To the left of x=- 2
Increasing Interval: To the right of x=- 2
Maximum Value: 61/4
Domain: All real numbers
Range: y ≤ 61/4
Increasing Interval: To the left of x= 52
Decreasing Interval: To the right of x= 52
For a quadratic function f(x)=ax^2+bx+c, the y-coordinate of the vertex is the minimum value of the function when a>0.
Let's identify the values of a, b, and c in the given quadratic function.
f(x)=4x^2+16x-3
⇕
f(x)= 4x^2+ 16x+( - 3)
Since a= 4 is greater than 0, the parabola will open upwards. This means it will have a minimum value, which is given by f ( - b2a ). Before we find the value of the function at this point, we need to substitute a= 4 and b= 16 in - b2a.
Now we have to calculate f(- 2). To do so, we will substitute - 2 for x in the given function.
This tells us that the minimum value of the function is - 19.
Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= 4 is greater than 0, the range is all values greater than or equal to the minimum value, - 19. Domain:& All real numbers Range:& y ≥ - 19
Since a= 4 is greater than 0, the function decreases to the left of the minimum value and increases to the right of the minimum value, which we know occurs at x=- 2. Decreasing Interval:& To the left of - 2 Increasing Interval:& To the right of - 2
For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.
Let's identify the values of a, b, and c in the given quadratic function.
h(x)=- x^2+5x+9
⇕
h(x)= - 1x^2+ 5x+ 9
Since a= - 1 is less than 0, the parabola will open downwards. This means it will have a maximum value, which is given by h ( - b2a ). Before we find the value of the function at this point, we need to substitute a= - 1 and b= 5 in - b2a.
a= - 1, b= 5
a(- b)=- a * b
- a/- b= a/b
Now we have to calculate h( 52 ). To do so, we will substitute 52 for x in the given function.
x= 5/2
(a/b)^m=a^m/b^m
a*b/c= a* b/c
a/b=a * 2/b * 2
a = 4* a/4
Add fractions
This tells us that the maximum value of the function is 614.
Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= - 1 is less than 0, the range is all values less than or equal to the maximum value, 614. Domain:& All real numbers Range:& y ≤ 61/4
Since a= - 1 is less than 0, the function increases to the left of the maximum value and decreases to the right of the maximum value, which we know occurs at 52. Increasing Interval:& To the left of 52 Decreasing Interval:& To the right of 52