Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
2. Characteristics of Quadratic Functions
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Exercise 49 Page 62

Practice makes perfect
a When the diver is still on the diving board, the distance to it is 0. To find the height of the diving board we must evaluate x=0 into f(x)=-9x^2+9x+1.
f(x)=-9x^2+9x+1
f( 0)=-9( 0)^2+9( 0)+1
f(0)=1
Therefore, the height of the diving board above water is 1 meter.
b To find the maximum height reached by the diver, we must find the y-coordinate of the vertex of the parabola by using the formula given below.
ccc x-coordinate & & y-coordinate x=-b/2a & & y=f(-b/2a) Since f(x)=-9x^2+9x+1, then a=-9 and b=9, which implies that x=- 92(-9)= 12.
f(x)=-9x^2+9x+1
f( 1/2)=-9( 1/2)^2+9( 1/2)+1
â–Ľ
Simplify right-hand side
f(1/2)= -9(1/4)+9(1/2)+1
f(1/2)= -9/4+9/2+1
f(1/2)= -9/4+18/4+1
f(1/2)= 9/4+1
f(1/2)= 9/4+4/4
f(1/2)= 9+4/4
f(1/2)= 13/4
f(1/2)= 3.25
The maximum height reached by the diver is 3.25 meters above water.
c Since the leading coefficient of f(x)=-9x^2+9x+1 is negative (-9), the parabola must open downward. This means that, from left to right it goes up until the vertex, and then goes down.

Thus, the diver is ascending from x=0 to the x-coordinate of the vertex which is, according to part B, x= 12. Consequently, after x=0.5 meters the diver is descending until hitting the water.

From the graph above, we can see that the diver entered the water 1.1 meters away from the diving board.