We will solve the given quadratic equation by using the Quadratic Formula.
ax2+bx+c=0⇔x=2a-b±b2−4ac
Let's identify the values of a,b, and c in our equation.
3x2+(-2)x+(-4)=0
We can see above that a=3,b=-2, and c=-4. Now we can substitute these values into the Quadratic Formula.