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We are given the inequality $-3+x>1$ and Mika's steps . In the first step, the goal is to move $-3$ to the right-hand side, and the inverse operation of subtracting $3$ is adding $3.$ $-3+x-3+x+3 >1⇕ >1−3 $
We can see that Mika added $3$ on the left-hand side but subtracted $3$ from the right-hand side. This is not correct since the operation must be the same on both sides to make sure that the equality still holds. Therefore, let's correct this error.
The correct solution set is $x>4$ and **not** $x>-2.$ We can graph this by using an open circle at $4.$ This indicates that $x=4$ is not part of the solution. Then we shade the values to the right of $4$ to indicate that all numbers greater than $4$ are solutions.