Expand menu menu_open Minimize Start chapters Home History history History expand_more
{{ item.displayTitle }}
navigate_next
No history yet!
Progress & Statistics equalizer Progress expand_more
Student
navigate_next
Teacher
navigate_next
{{ filterOption.label }}
{{ item.displayTitle }}
{{ item.subject.displayTitle }}
arrow_forward
No results
{{ searchError }}
search
menu_open
{{ courseTrack.displayTitle }}
{{ statistics.percent }}% Sign in to view progress
{{ printedBook.courseTrack.name }} {{ printedBook.name }}
search Use offline Tools apps
Login account_circle menu_open

Solving Compound Inequalities

Solving Compound Inequalities 1.10 - Solution

arrow_back Return to Solving Compound Inequalities
a

When an inequality is multiplied or divided by a negative number, the inequality symbol must be flipped. This has not been done in the last step. -4x<8x<-2\begin{aligned} \text{-}4x < 8 \\ x < \text{-}2 \end{aligned} Ron-Jon divided both sides with -4\text{-}4 but he forgot to flip the sign.

b

Let's start from the beginning. Remember the rule for inequalities when multiplying or dividing by a negative.

13x<17x+813x\lt 17x+8
-4x<8\text{-}4x\lt 8
x>-2x\gt \text{-}2
The inequality is, therefore, true if x>-2.x \gt \text{-}2. Ron-Jon's solutions should have been as follows.
inequality that has been solved incorrectly