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| 10 Theory slides |
| 9 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Kriz wants to play some video games with their little cousin. However, Kriz's cousin has not finished his homework yet.
Kriz does not want to spill out the answer right away. They want to help their cousin understand math! Kriz's cousin only knows how to use multiplication tables.
While waiting for their cousin to finish his homework,Kriz plays a single-player game video game.
Use the Power of a Product Property and the Power of a Power Property.
(a⋅b)m=am⋅bm
(am)n=am⋅n
Multiply
Multiply
Any non-zero real number raised to the power of 0 is equal to 1.
a0=1
If a is a non-zero real number and n is a positive integer, then a raised to the power of -n is equal to 1 over a raised to the power of n.
a-n=an1
Use the Product of Powers Property and the Zero Exponent Property. Remember, any number or expression multiplied by 1 is equal to itself.
Kriz's cousin has finally finished his homework, so they can play a cooperative game together.
Use the Quotient of Powers Property and the Negative Exponent Property to reach the final answer.
Kriz's cousin needs to finish his homework. He is down to the last multiplication problem.
Note that both 16 and 9 are perfect squares. This can be shown in the multiplication table.
Finally, the answer can be given using only information from the multiplication table.
We are asked to pair the numbers that are equal in value. Let's start by noting that every number of the left column is written as a power of either 2 or 3. 2^4 2^6 3^4 3^8 Let's try to write the bases of the numbers in the right column as powers of 2 and of 3 as well. This will make it easier to match the two columns. 4 = 2^2 8 = 2^3 9 = 3^2 Now we can use the Power of a Power Property on each of the possible values on the right to simplify them. Let's rewrite 4^2 first. 4^2 &= (2^2)^2 &= 2^(2 * 2) &= 2^4 We can rewrite the rest of the numbers in a similar fashion.
Number | Rewrite | Use Power of a Power Property | Simplify |
---|---|---|---|
4^2 | (2^2)^2 | 2^(2 * 2) | 2^4 |
8^2 | (2^3)^2 | 2^(3 * 2) | 2^6 |
9^2 | (3^2)^2 | 3^(2 * 2) | 3^4 |
9^4 | (3^2)^4 | 3^(2 * 4) | 3^8 |
We can now pair every number. 2^4 → 4^2 2^6 → 8^2 3^4 → 9^2 3^8 → 9^4
We are asked to sort the given list of numbers from least to greatest. Let's start with 2^0. We know that because of the Zero Exponent Property, 2^0 is equal to 1. 2^0 = 1 Next, note that 2^3 means that 2 is being multiplied by itself three times. Likewise, 2^6 means that 2 is being multiplied by itself six times. This means that 2^6 is greater than 2^3. We can use this information to sort the numbers with non-negative powers. 2^0 < 2^3 < 2^6 Let's now use the Negative Exponent Property to convert the negative powers into positive powers. 2^(- 1) &= 1/2 [0.8em] 2^(- 3) &= 1/2^3 Both of these numbers are less than 1, but we still need to determine which is less than the other. Note that 2^3 is equal to 8, so let's rewrite 2^(- 3). 2^(-3) &= 1/2^3 [0.8em] &= 1/8 This means that 2^(- 1) is one half and 2^(- 3) is one-eighth, and we know that 18 is less than 12.
Knowing this, we can sort all of the numbers from least to greatest. &2^(- 3) &2^(- 1) &2^0 &2^3 &2^6
Consider a cube with a side length of x1.
We want to find the volume of the given cube.
Let's use the formula for the volume of a cube. V=s^3 Substitute 1x for s in the above formula. V= (1/x)^3 Next, use the Negative Exponent Property to rewrite the right-hand side of the above equation. V &= ( 1/x ) ^3 [0.8em] &= (x^(- 1))^3 We can now use the Power of a Power Property to simplify the expression. V &= (x^(- 1))^3 [0.75em] &= x^(- 1 * 3) [0.75em] &= x^(- 3) This means that the volume of the cube is given by the expression x^(- 3).