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(- 12, - 5)
When solving a system of equations using substitution, there are three steps.
Consider the given equations, we need to isolate one of the variables. Let's start by isolating x in Equation I.
(I): LHS+x=RHS+x
(I): LHS-2=RHS-2
Now that we've isolated x, we can solve the system by substitution.
(II):x= 2y-2
(II):Distribute - 4
(II): Subtract term
(II): LHS-8=RHS-8
(II): .LHS /(-3).=.RHS /(-3).
(II): Rearrange equation
Now, to find the value of x, we need to substitute y=-5 into either one of the equations in the given system. Let's use the first equation.
(I):y= - 5
(I): a(- b)=- a * b
(I):Subtract term
The solution, or point of intersection, to this system of equations is the point (- 12, - 5).
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= -12, y= -5
(I), (II): Multiply
(I), (II): Add terms
Because both equations are true statements, we know that our solution is correct.