2. Solving Systems Using Substitution
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(- 12, - 5)
When solving a system of equations using substitution, there are three steps.
(I): LHS+x=RHS+x
(I): LHS-2=RHS-2
(II):x= 2y-2
(II):Distribute - 4
(II): Subtract term
(II): LHS-8=RHS-8
(II): .LHS /(-3).=.RHS /(-3).
(II): Rearrange equation
(I):y= - 5
(I): a(- b)=- a * b
(I):Subtract term
(I), (II): x= -12, y= -5
(I), (II): Multiply
(I), (II): Add terms