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(-5/7,22/7)
When solving a system of equations using substitution, there are three steps.
For this exercise, y is already isolated in one equation, so we can skip straight to solving!
(II):y= x+3
(II):Distribute 4
(II):Add terms
(II):LHS-12=RHS-12
(II): .LHS /7.=.RHS /7.
Now, to find the value of y, we need to substitute x=- 57 into either one of the equations in the given system. Let's use the first equation.
The solution, or point of intersection, to this system of equations is the point (- 57,2 27).
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= - 57, y= 2 27
(II): a bc=a* c+b/c
(II): Multiply fractions
(I), (II): Add terms
(II): Calculate quotient
Because both equations are true statements, we know that our solution is correct.