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(3,5)
When solving a system of equations using substitution, there are three steps.
For this exercise, y is already isolated in one equation, so we can skip straight to solving!
(I):y= 3x-4
(I):Distribute 5
(I):Add terms
(I):LHS+20=RHS+20
(I):.LHS /13.=.RHS /13.
Now, to find the value of y, we need to substitute x=3 into either one of the equations in the given system. Let's use the second equation.
(II):x= 3
(II):Multiply
(II):Subtract term
(II):Rearrange equation
The solution, or point of intersection, to this system of equations is the point (3,5).
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= 3, y= 5
(I), (II): Multiply
(I), (II): Add and subtract terms
Because both equations are true statements, we know that our solution is correct.