Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
2. Solving Systems Using Substitution
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Exercise 25 Page 375

What is the sum of the three angles of a triangle?

18^(∘), 72^(∘)

Practice makes perfect

We are told that the measure of an acute angle in a right triangle is four times the measure of the other acute angle, and we are asked to find those measures. To do so, we will write and solve a System of Equations. If we call the first acute angle x and the second y, we can write this relationship as the following equation. x=4y We can use the fact that the triangle is a right triangle and that the sum of the three angles for any triangle is 180^(∘) to form our second equation. x+y+90=180 Therefore, the system of equations can be written as follows. x=4y & (I) x+y+90=180 & (II) We will solve it using the Substitution Method. Since the x-variable is already isolated in Equation (I), we are going to substitute its equivalent expression in Equation (II).

x=4y & (I) x+y+90=180 & (II)
x=4y 4y+y+90=180
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Solve Equation (II) for y
x=4y 5y+90=180
x=4y 5y=90
x=4y y=18

We found that y=18. To solve for x, we will substitute 18 for y in Equation (I).

x=4y y=18
x=4* 18 y=18
x=72 y=18

We have found that x=72. Therefore, the solution of the system of equations, which is the point of intersection of the lines, is (18,72). That means that the measures of the acute angles are 18^(∘) and 72^(∘).