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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

2. Solving Systems Using Substitution

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Exercise 46 Page 377

You'll need to substitute 0 for y and solve.

-8

Practice makes perfect

Think of the point where the graph of an equation crosses the x-axis. The y-value of that (x, y) coordinate pair is 0, and the x-value is the x-intercept. To find the x-intercept of the equation, we should substitute 0 for y and solve for x.

2y-3x=24

y= 0

2( 0)-3x=24

Zero Property of Multiplication

-3x=24

.LHS /-3.=.RHS /-3.

x=-8

An x-intercept of -8 means that the graph passes through the x-axis at the point (-8,0).

Subchapter links

Lesson Check p.375

Practice and Problem-Solving Exercises p.375-377

Standardized Test Prep p.377

Mixed Review p.377