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The number of boys plus the number of girls equals 350.
20
There are 350 students taking algebra and the ratio of boys to girls is 33:37. We need to find how many more girls than boys are taking the course. To do so we will write and solve a system of equations.
Let b be the number of boys and g be the number of girls taking algebra. As there are 350 students, we can write our first equation as follows.
b+ g=350
Let's use the given ratio to write the second equation. The ratio of boys to girls
can be written as bg. This fraction we have been told is equal to 33:37= 3337.
When solving a system of equations non-linear terms, such as bg, we must begin by isolating one of the terms. Therefore, we will begin our solution by isolating b in Equation (II). After that we will substitute the resulting expression into Equation (I).
(II): LHS * g=RHS* g
(II): a/c* b = a* b/c
(I): b= 33g/37
(I): a = 37* a/37
(I): Add fractions
(I): LHS * 37=RHS* 37
(I): .LHS /70.=.RHS /70.
We found that g= 185. To find b, we will substitute 185 for g in Equation (II).
(I): g= 185
(I): Calculate quotient and product
We found that b= 165.
We can interpret this solution, b= 165 and g= 185, as follows. The number of $ boys$ taking algebra is $ 165.$ The number of $ girls$ taking algebra is $ 185.$ The question asks how many more girls than boys are taking the course, so our answer will be 185- 165=20.