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(-11,-19)
When solving a system of equations using substitution, there are three steps.
Consider the given system of equations, we need to isolate one of the variables. Let's start by isolating y in Equation I.
Now that we've isolated y, we can solve the system by Substitution.
(II):y= 2x+3
(II):Distribute - 2
(II):Subtract terms
(II):LHS+6=RHS+6
(II): LHS * (-1)=RHS* (-1)
Now, to find the value of y, we need to substitute x=-11 into either one of the equations in the given system. Let's use the first equation.
(I):x= - 11
(I): a(- b)=- a * b
(I):Add terms
The solution, or point of intersection, to this system of equations is the point (- 11,- 19).
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= -11, y= -19
(I), (II): Multiply
(I), (II): Add terms
Because both equations are true statements, we know that our solution is correct.