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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

2. Solving Systems Using Substitution

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Exercise 44 Page 377

Use the Substitution Method to solve the system.

14.4

Practice makes perfect

We can use the Substitution Method to solve the system of equations. Since the exercise only asks for the x-coordinate, we do not need to solve for y. We just need to isolate y, substitute, and solve for x.

2x+3y=144 & (I) y-x=24 & (II)

(II):LHS+x=RHS+x

2x+3y=144 y=x+24

(I):y= x+24

2x+3( x+24)=144 y=x+24

(I):Distribute 3

2x+3x+72=144 y=x+24

(I):Add terms

5x+72=144 y=x+24

(I):LHS-72=RHS-72

5x=72 y=x+24

(I):.LHS /5.=.RHS /5.

x=14.4 y=x+24

The x-coordinate of the solution to the system is 14.4.

Subchapter links

Lesson Check p.375

Practice and Problem-Solving Exercises p.375-377

Standardized Test Prep p.377

Mixed Review p.377