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(255/11, 64/11)
When solving a system of equations using substitution, there are three steps to follow.
For this exercise, x is already isolated in one equation, so we can skip straight to solving!
(II):x= 4y
(II):Multiply
(II):Subtract term
(II): .LHS /11.=.RHS /11.
Now, to find the value of x, we need to substitute y= 7011 into either one of the equations in the given system. Let's use the first equation.
(I):y= 70/11
(I): Multiply
(I): Rearrange equation
The solution to this system of equations is the point ( 28011, 7011). We can also rewrite these solutions as mixed numbers.
(I): Write as a sum
(I): Split into factors
(I): Write fraction as a mixed number
(II): Write as a sum
(II): Split into factors
(II): Write fraction as a mixed number
To check our answer, we will substitute our solution into both equations. If doing so results in true statements, then our solution is correct.
(I), (II): x= 280/11, y= 70/11
(I), (II): Multiply
(II): Subtract fractions
(II): Calculate quotient
Because both equations are true statements, we know that our solution is correct.