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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

6. Trapezoids and Kites

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Exercise 65 Page 529

Recall that in kites exactly one pair of opposite angles is congruent.

Belinda is correct, Bedagi is not. See solution.

Practice makes perfect

Let's begin with recalling that in kites exactly one pair of opposite angles is congruent.

In our exercise this means that ∠ D and ∠ B are congruent, and both of them have a measure of 100^(∘).

To find m∠ A, let's use the fact that the sum of the measures of all angles in every quadrilateral is equal to 360^(∘).

m∠A+ 100^(∘)+ 100^(∘)+45^(∘)=360^(∘)

Add terms

m∠A+245^(∘)=360^(∘)

LHS-245^(∘)=RHS-245^(∘)

m∠A=115^(∘)

Since m∠A=115^(∘), Belinda is correct, and Bedagi is not.

Subchapter links

Exercises p.526-530