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m=y_2-y_1/x_2-x_1 In this formula, (x_1,y_1) and (x_2,y_2) are points on the line or segment. Using this formula, we can evaluate the slope of each side of a quadrilateral.
Substitute values
a-(- b)=a+b
Add and subtract terms
| Side | Points | Slope Formula | Slope |
|---|---|---|---|
| AB | ( -3, 2) & ( 1,3) | 3- 2/1-( -3) | m_(AB)=1/4 |
| BC | ( 1, 3) & ( 5, ) | - 3/5- 1 | m_(BC)=3/4 |
| CD | ( 5, 0) & ( 5,-4) | -4- 0/5- 5 | Undefined |
| DA | ( 5, -4) & ( -3,2) | 2-( -4)/-3- 5 | m_(DA)=3/4 |
Since m_(AB)=m_(DA), segments AB and DA are parallel. This means that this quadrilateral is a trapezoid, as it has one pair of opposite parallel sides. To determine if this trapezoid is isosceles, we need to check if its legs are congruent. We can use the Distance Formula. MN=sqrt((x_N-x_M)^2+(y_N-y_M)^2) Let's evaluate this formula for AB and CD.
| Segment | Points | Distance Formula | Length |
|---|---|---|---|
| AB | ( -3, 2) & ( 1,3) | sqrt(( 1-( -3))^2+(3- 2)^2) | AB=sqrt(17) |
| CD | ( 5, 0) & ( 5,-4) | sqrt(( 5- 5)^2+(-4- 0)^2) | CD=4 |
Since legs of this trapezoid have different measures, trapezoid ABCD is not isosceles.
y=- x+1 ⇒ y= -1x+1 In the given equation, the slope is -1 and it is not the same as the slope of the bases, which is 34 (we found this in the previous part). Therefore, the midsegment is not contained in the line with equation y=- x+1.
To find the length of the midsegment in ABCD, we need to start with evaluating the lengths of the bases in this trapezoid. To do this, let's use the Distance Formula we recalled in Part A.
| Segment | Points | Distance Formula | Length |
|---|---|---|---|
| BC | ( 1, 3) & ( 5, ) | sqrt(( 5- 1)^2+( - 3)^2) | BC=5 |
| AD | ( -3, 2) & ( 5,-4) | sqrt(( 5-( -3))^2+(-4- 2)^2) | AD=10 |
a= 5, b= 10
Add terms
a/c* b = a* b/c
Calculate quotient